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2 years ago

IA man buys buys 62 litres of petrol dailly

Mathematics

2 answers:

Goryan [66]2 years ago

3 0

Answer:

372

Step-by-step explanation:

62 x 6 = 372

Otrada [13]2 years ago

3 0

Answer:

372 liters that is the right answer

You might be interested in

Which functions have an axis of symmetry of x = -2? Check all that apply. A. f(x) = x^2 + 4x + 3 B. f(x) = x^2 - 4x - 5 C. f(x)

Snowcat [4.5K]

Answer:

A. f(x) = x^2 + 4x + 3

D. f(x) = -2x^2 - 8x + 1

Step-by-step explanation:

The axis of symmetry is found by h = -b/2a where ax^2 +bx +c

A. f(x) = x^2 + 4x + 3

h = -4/2*1 = -2 x=-2

B. f(x) = x^2 - 4x - 5

h = - -4/2*1 = 4/2 =2 x=2 not -2

C. f(x) = x^2 + 6x + 2

h = -6/2*1 = -3/2 = x=-3/2 not -2

D. f(x) = -2x^2 - 8x + 1

h = - -8/2*-2 = 8/-4 =-2 x=-2

E. f(x) = -2x^2 + 8x - 2

h = - 8/2*-2 = -8/-4 =2 x=2 not -2

7 0

3 years ago

The scale on a map is 1: 75 000. (a) Calculate the ACTUAL distance, in km, between two places which are 16 cm apart on the map.

finlep [7]

Answer:

a. 1 200 000 km

b. 0.000 773 cm

c. 67 500 000 000 km²

d. 0.000 000 016 cm²

Step-by-step explanation:

a. Calculate the ACTUAL distance, in km, between two places which are 16 cm apart on the map.

Since the scale is 1 : 75000 that is 1 cm : 75000 km, we want to find the actual distance of 16 cm on the map. Let x be the actual distance in km.

So, 1 cm : 75000 km = 16 cm : x km

So, 1 cm/75000 km = 16 cm/x km

Thus x km = 16 cm × 75000 km/1 cm = 1 200 000 km

(b) Calculate length of a road on the map which is 0.58 km.

Let y be the length of road on the map. So, using our scale

1 cm : 75000 km = y cm : 0.58 km

So, 1 cm/75000 km = y cm/0.58 km

Thus y cm = 0.58 km × 1 cm/75000 km = 0.000 773 cm

(c) Calculate, in km², the ACTUAL area of a lake which is 12 cm2 on the map.

Since the scale is 1 : 75000 , the scale for the area would be the square of this. So, 1² : 75000² = 1 : 5 625 000 000 which is 1 cm² : 5 625 000 000 km²

Let z be the actual area of the lake.

So, 1 cm² : 5 625 000 000 km² = 12 cm² : z km²

So, 1 cm²/5 625 000 000 km² = 12 cm²/z km²

Thus z km² = 12 cm² × 5 625 000 000 km²/1 cm² = 67 500 000 000 km²

(d) Calculate the area of a play field on the map which has has an actual area of 90 km².

Let a represent the area of the play field on the map. Using our scale for the area,

1 cm² : 5 625 000 000 km² = a cm² : 90 km²

So, a cm² = 90 km² × 1/5 625 000 000 km² = 0.000 000 016 cm²

4 0

3 years ago

Please help me, I don't understands this question

Rudik [331]

It would be none because the same would be the reciprocal which would be (-7, -8.75)

8 0

3 years ago

Determine whether each event is possible or impossible on a 6-sided cube where the numbers are 1 through 6.

tankabanditka [31]

Answer:

Step-by-step explanation:

Possible:

Rolling a 1

Rolling a number less than 7

Rolling an even number

Impossible:

Rolling a number greater than 10

Rolling an 8

4 0

2 years ago

Pollution Rates Assignment

stepan [7]

Answer:

1. a) 4.8 lb

I) 8%

II) 0.384 lb

2. a) 12.5 lb

I) 8%

II) 1 lb

Step-by-step explanation:

Let's begin by listing out the given variables:

mass of pesticide (m) = 12 lb,

40WP (40 weight percent) means the active ingredient comprises 40% of the total mass of the pesticide

a) amount of active ingredient = mass of the pesticide * weight percentage of the active ingredient

x = 12 * 40% = 12 * 0.4

x = 4.8 lb

I. If the soil has an absorption rate of 92%, that means 8% will go into the run-off

The percentage of active ingredient that will end up in the run-off = the percentage of the active ingredient (100%) - the absorption rate

y = (100 - 92)%

y = 8%

II. amount of of active ingredient that will end up in the run-off = amount of active ingredient * the percentage of active ingredient that will end up in the run-off

z = x * y = 4.8 * 8% = 4.8 * 0.08

z = 0.384 lb

2. Let's list out the variables given, we have:

mass of pesticide = 25 lb, weight percent of active ingredient = 50% = 0.5

amount of active ingredient = mass of the pesticide * weight percentage of the active ingredient

x = 25 * 0.5

x = 12.5 lb

I. If the soil has an absorption rate of 92%, that means 8% will go into the run-off

The percentage of active ingredient that will end up in the run-off = the percentage of the active ingredient (100%) - the absorption rate

y = (100 - 92)%

y = 8%

II. amount of of active ingredient that will end up in the run-off = amount of active ingredient * the percentage of active ingredient that will end up in the run-off

z = x * y = 12.5 * 8% = 12.5 * 0.08

z = 1 lb

7 0

3 years ago