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3 years ago

Explain how you can use your compass to construct one-fourth the length of a segment.

Mathematics

1 answer:

kogti [31]3 years ago

7 0

Answer:

You caluculate the value of the segment then multiply it by 1/4. After that you move the compass to match the radius of the segment

Step-by-step explanation:

Sorry if that didnt make sense

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Find the slope of the graph.

slavikrds [6]

Answer:

the slope is 4/3

Step-by-step explanation:

slope is also called rise over run you start at one point and count how many spaces it is up to the next point then across

8 0

3 years ago

I don’t understand this problem

ikadub [295]

Hello! the answer is c

First of all let's eliminate the answers that do not make sense. For A. numbers are NOT irrational because they are a fraction. Numbers are also not irrational because they are a repeating number. C and D are both correct as fractions and terminating decimals are both rational numbers.

34/3≈11.33333333

By using a certain formula you can convert repeating decimals to a fraction. But most people know that .3333333 is 1/3. This gives us 11 1/3 as our answer. So what does it match? It is not a terminating decimal. It repeats but can be written as a fraction. Therefore our answer is C) Rational, because it is a fraction.

I hope this helps!

bran-list please

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3 years ago

Which part of the graph best represents the solution set to the system of inequalities y ≤ x + 1 and y + x ≤ –1?

Lady bird [3.3K]

The part of the graph that best represents the solution set to the system of inequalities y ≤ x + 1 and y + x ≤ –1 is Part C.

8 0

3 years ago

A 100 gallon tank initially contains 100 gallons of sugar water at a concentration of 0.25 pounds of sugar per gallon suppose th

Vsevolod [243]

At the start, the tank contains

(0.25 lb/gal) * (100 gal) = 25 lb

of sugar. Let $S(t)$ be the amount of sugar in the tank at time $t$ . Then $S(0)=25$ .

Sugar is added to the tank at a rate of P lb/min, and removed at a rate of

$\left(1\frac{\rm gal}{\rm min}\right)\left(\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm gal}\right)=\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm min}$

and so the amount of sugar in the tank changes at a net rate according to the separable differential equation,

$\dfrac{\mathrm dS}{\mathrm dt}=P-\dfrac S{100}$

Separate variables, integrate, and solve for S.

$\dfrac{\mathrm dS}{P-\frac S{100}}=\mathrm dt$

$\displaystyle\int\dfrac{\mathrm dS}{P-\frac S{100}}=\int\mathrm dt$

$-100\ln\left|P-\dfrac S{100}\right|=t+C$

$\ln\left|P-\dfrac S{100}\right|=-100t-100C=C-100t$

$P-\dfrac S{100}=e^{C-100t}=e^Ce^{-100t}=Ce^{-100t}$

$\dfrac S{100}=P-Ce^{-100t}$

$S(t)=100P-100Ce^{-100t}=100P-Ce^{-100t}$

Use the initial value to solve for C :

$S(0)=25\implies 25=100P-C\implies C=100P-25$

$\implies S(t)=100P-(100P-25)e^{-100t}$

The solution is being drained at a constant rate of 1 gal/min; there will be 5 gal of solution remaining after time

$1000\,\mathrm{gal}+\left(-1\dfrac{\rm gal}{\rm min}\right)t=5\,\mathrm{gal}\implies t=995\,\mathrm{min}$

has passed. At this time, we want the tank to contain

(0.5 lb/gal) * (5 gal) = 2.5 lb

of sugar, so we pick P such that

$S(995)=100P-(100P-25)e^{-99,500}=2.5\implies\boxed{P\approx0.025}$

5 0

3 years ago

Please someone help me and explain this question to me (the last question starting with a straw)

Anastasy [175]

Each straw is 4-1/8 inches long.
You have one gigantic piece of straw material, 123-3/4 inches long.
How many straws can you cut it up to make ?

===> (123-3/4) divided by (4-1/8) straws.

Each one costs $0.015 to make.
So, once you find the number of short straws you have,
multiply

===> (the number of short straws) x ($0.015) .

That'll tell you how much it costs to make all of them.

Now you know how to do it on your own.
If you don't get 30 straws and $0.45 , please try again.

6 0

2 years ago

Explain how you can use your compass to construct one-fourth the length of a segment.​

Explain how you can use your compass to construct one-fourth the length of a segment.