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3 years ago

Explain how you can use your compass to construct one-fourth the length of a segment.

Mathematics

1 answer:

kogti [31]3 years ago

7 0

Answer:

You caluculate the value of the segment then multiply it by 1/4. After that you move the compass to match the radius of the segment

Step-by-step explanation:

Sorry if that didnt make sense

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3 years ago

Please help me I need help please

MakcuM [25]

Answer:

p = 4

Step-by-step explanation:

Given equation:

$x^2+(p-3)y^2-4x+6y-16=0$

<u>Standard equation of a circle:</u>

$(x-a)^2+(y-b)^2=r^2$

(where $(a,b)$ is the centre of the circle, and $r$ is the radius)

If you expand this equation, you will see that the coefficient of $y^2$ is always one.

Therefore, $p-3=1$

$\implies p=1+3=4$

<u>Additional information</u>

To rewrite the given equation in the standard form:

$\implies x^2+y^2-4x+6y-16=0$

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Answer:

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Explain how you can use your compass to construct one-fourth the length of a segment.​

Explain how you can use your compass to construct one-fourth the length of a segment.