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vova2212 [387]
3 years ago
11

How can i solve thistan2x/(tan4x-tan2x)​

Mathematics
2 answers:
Maslowich3 years ago
5 0

Answer: = cos 4x

\frac{tan2x}{tan4x-tan2x}\\\\=\frac{tan2x}{\frac{2tan2x}{1-tan^{2}2x }-tan2x }\\\\=\frac{tan2x(1-tan^{2}2x) }{2tan2x-tan2x(1-tan^{2}2x) }\\\\=\frac{tan2x(1-tan^{2}2x) }{tan2x(2-1+tan^{2}2x) }\\\\=\frac{1-tan^{2}2x }{1+tan^{2}2x }     \\\\=\frac{1-\frac{sin^{2}2x }{cos^{2}2x } }{1+\frac{sin^{2}2x }{cos^{2}2x } }\\\\=\frac{cos^{2}2x-sin^{2}2x  }{cos^{2}2x+sin^{2}2x  }  \\\\=\frac{cos4x}{1}\\\\=cos4x

Step-by-step explanation:

pshichka [43]3 years ago
3 0
the answer is yes i did this before so hope that helps
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The function f(x)=-(x+5)(x+1) is shown. What is the range of the function?​
Vesna [10]

Answer:

(- ∞, 4 ]

Step-by-step explanation:

To determine the range we require the coordinates of the vertex

The vertex lies on the axis of symmetry which is positioned at the midpoint of the zeros.

To obtain the zeros, equate f(x) to zero, that is

-(x + 5)(x + 1) = 0

Equate each factor to zero and solve for x

x + 5 = 0 ⇒ x = - 5

x + 1 = 0 ⇒ x = - 1

x_{vertex} = \frac{-5-1}{2} = \frac{-6}{2} = - 3

Substitute x = - 3 into f(x) for corresponding value of y

f(- 3) = - (- 3 + 5)(- 3 + 1) = - (2)(- 2) = 4

Vertex = (- 3, 4)

Since a = - 1 then vertex is a maximum, hence

range is (- ∞, 4 ]

4 0
3 years ago
The two triangles are similar, what is the measure of angle L?
gtnhenbr [62]
ABC is similar to JKL. Notice how C is the right angle (90 degrees) as shown by the square angle marker. Angle L matches up with angle C. They are the last letters of ABC and JKL

So angle L = 90 degrees as well
4 0
3 years ago
Read 2 more answers
> Reflect the shape A in the 3-axis.
suter [353]

Answer:

(4,3)

Step-by-step explanation:

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7 0
3 years ago
Find the sum of the polynomials below: (4x? + 5x5 + 1x+6) + (10x7 + 6x5 - 4x + 4)​
yaroslaw [1]

Answer:

10 x^7 + 6 x^5 - 4 x + 4

Step-by-step explanation:

6 0
3 years ago
Pythagorean Theorem in Cones. I need a lot of help.
Nadya [2.5K]
The Pythagorean Theorem formula is listed below. It can only be applied to right triangles.

(side1)^2 + (side2)^2 = (hypotenuse)^2

Since we are given that the base is 8cm, we know that the side of one triangle is 4cm. We are also given that the hypotenuse is 8cm. The height of the cone will be one of the short sides. If we plug these numbers into the formula, we get the following...

4^2 + height^2 = 8^2 

If we solve for height, we get the following...

height = sqrt(8^2 - 4^2) = sqrt(64 - 16) = sqrt(48)

Since we are only asked for what is inside the square root, our answer is 48.
3 0
3 years ago
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