If Andy has 102 coins mixed with dimes and quarters and monetary value of $17.10 then he has 56 dimes and 42 quarters.
Given number of coins Andy has is 102 and montary value of all coins is $17.10.
We have to determine number of dimes and quarters.
1 dime=$0.10
1 quarter=$0.25
Suppose the number of dimes be x and number of quarters be y.
The equations are:
0.10x+0.25y=17.10------------1
x+y=102-------------2
from equation 2, y=102-x
Put the value of y=102-x in equation 1
0.10x+0.25(102-x)=17.10
0.10x+25.5-0.25x=17.10
-0.15x=17.10-25.5
-0.15x=-8.4
x=8.4/0.15
x=56
Put the value of x in y=102-x
y=102-56
y=46
Hence Andy has 56 number of dimes and 46 quarters.
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Fist you need to substitute the value of R into the equation
25-6(3)
Now you simply
First multiple 6(3)
25-6(3)
25-18
Now solve!
25-18
7
The answer is 7
Answer:
14 hours
Step-by-step explanation:
Let's call the task 3x
The older bro does twice as younger so it would be 2x long and younger brother work x long
Since the totsl of work is 3x = 21 x woul be 21÷3 = 7
the older brother must work 2 × 7 = 14 hours long
Answer:
4 1/12
Step-by-step explanation:
a = 5/6 b = 3 1/4 = 13/4
To add 5/6 + 13/4, we have to make the denominators the same:
20/24 + 78/24 = 98/24
To make it back to a mixed fraction:
4 2/24
4 1/12
Answer:
2.4x = 1.2x + 15
13
Step-by-step explanation:
just did it
