Answer:
78% probability it contains no defects
Step-by-step explanation:
We have that:
10% have defects in shafts only.
8% have defects in bushings only.
4% have the two types of defects.
An assembly is selected arandom, what is the probability it contains no defects
Either it has at least one defect, or it has no defects. The sum of these probabilities is 100%. So
D + ND = 100
Probability that it has a defect
D = 10 + 8 +4 = 22%
No defects:
22 + ND = 100
ND = 78
78% probability it contains no defects
Answer:
AO and OC
x+8 and 16-x
x+8 = 16-x
x+x= 16-8
2x= 8
x= 8/2
x=4
DO and OB
2y+13 and 5y+4
2y+13 = 5y+4
2y-5y= 4-13
-3y = -9
y= 9/3
y= 3
Step-by-step explanation:
i hope this helps
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Answer:
Step-by-step explanation:
3x+ 1/3 for x<= -1
6x-27 for x >4
Yes it is a solution because if you take the equation and plug the point in for the x and y :
4 (2) + 3 (3) < 20
8 + 9 < 20
17 < 20
which is true
10 (2) + (3) > 10
20 + 3> 10
23>10
which is also true