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2 years ago

The graph of the function f(x)= x^2 − 4x + 6 is shown here. What is its axis of symmetry? A. x = 0 B. x = 2 C. x = 6 D. x = -2

Mathematics

1 answer:

wlad13 [49]2 years ago

6 0

Answer:

B. x=2

Step-by-step explanation:

If you split it right down the middle and reflect it is exact same.

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Different rose bushes are grown in a g reenhouse for two months. The number of flowers on each bush is counted at the end of the

Oliga [24]

1. Rose bushes
2. Number of flowers on each bush
3. None, unless there is an original rose bush they used before the experiment

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2 years ago

Find the difference of (t-8)-(t-15)

Vsevolod [243]

I think u should try (t-23) because -8 minus - 15 is = to 23 so yeah add the t in front of it

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3 years ago

A quadratic function in vertex form whose graph has a vertex of (-4,6) and passes through the point (-1,9)

scZoUnD [109]

Couldnt you just do the X's together and the Y's and your answer after you divide by each??

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3 years ago

The acceleration of an object (in m/s^2) is given by the function a(t) = 9 sin(t). The initial velocity of the object is v(0) =

pentagon [3]

a) Acceleration is the derivative of velocity. By the fundamental theorem of calculus,

$v(t)=v(0)+\displaystyle\int_0^ta(u)\,\mathrm du$

so that

$v(t)=\left(-11\frac{\rm m}{\rm s}\right)+\int_0^t9\sin u\,\mathrm du$

$\boxed{v(t)=-\left(2+9\cos t)\right)\frac{\rm m}{\rm s}}$

b) We get the displacement by integrating the velocity function like above. Assume the object starts at the origin, so that its initial position is $s(0)=0\,\mathrm m$ . Then its displacement over the time interval [0, 3] is

$s(0)+\displaystyle\int_0^3v(t)\,\mathrm dt=-\int_0^3(2+9\cos t)\,\mathrm dt=\boxed{-6-9\sin3}$

c) The total distance traveled is the integral of the absolute value of the velocity function:

$s(0)+\displaystyle\int_0^3|v(t)|\,\mathrm dt$

$v(t)$ for $0\le t$ and $v(t)\ge0$ for $\cos^{-1}\left(-\frac29\right)\le t\le3$ , so we split the integral into two as

$\displaystyle\int_0^{\cos^{-1}\left(-\frac29\right)}-v(t)\,\mathrm dt+\int_{\cos^{-1}\left(-\frac29\right)}^3v(t)\,\mathrm dt$

$=\displaystyle\int_0^{\cos^{-1}\left(-\frac29\right)}(2+9\cos t)\,\mathrm dt-\int_{\cos^{-1}\left(-\frac29\right)}^3(2+9\cos t)\,\mathrm dt$

$\displaystyle=\boxed{2\sqrt{77}-6+4\cos^{-1}\left(-\frac29\right)-9\sin3}$

4 0

3 years ago

How do we find the angles for an irregular trapezoid?

bogdanovich [222]

Answer:

all angles must add up to 180 to be a trapizoid so if they dont add up then its irregular

Step-by-step explanation:

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2 years ago