Calculate the length for y

Real numbers x and y satisfy x + xy^2 = 250y, x - xy^2 = -240y. Enter all possible values of x, separated by commas.

agasfer [191]

Answer:

-35,35,0

Step-by-step explanation:

Let's organise our information :

x+xy²=250y
x-xy²= -240y

Now let's add them together :

x+xy²+x-xy²=250y-240y
2x=10y
x=5y ⇒ y= x/5

Let's replace y by x/5 in the first equation :

x+x*(x/5)²=250*(x/5)
x+ (x∧3)/25 = 50x
49x-(x∧3)/25=0
x(49-(x²/25))=0
x=0 or 49-(x²/25)=0
x=0 or 49= x²/25
x=0 or x²=1225
x=0 or x= $\sqrt{1225}$ or x= - $\sqrt{1225\\}$
x=0 or x=35 or x= -35

so x=[0,35,(-35)]

4 0

3 years ago

Read 2 more answers

BRAINLIEST ANSWER WINS! A satellite is to be put into an elliptical orbit around a moon as shown below. A vertical ellipse is sh

bekas [8.4K]

Answer:

D. x²/1953² + y²/ 1466² = 1

Step-by-step explanation:

==>Given:

Radius of spherical moon = 1000km

Distance of satellite from moon surface = 953km to 466km

==>Required:

Derived equation of ellipse

==>Solution:

The formula for driving an equation of ellipse is given as:

x²/a² + y²/b² = 1

Where,

a = length of the semi-major axis, while,

b = length of the semi-major axis

Since we are told that the satellite distance to the surface of the moon varies from 953km to 466km, values of a and b is calculated by summing each length to the radius of the moon as follows:

a = radius of moon + the larger distance of the satellite = 1000+953 = 1,953km

b = radius of moon + the smaller distance of the satellite = 1000+466 = 1,466km

Thus, the equation of the ellipse would be:

x²/1953² + y²/ 1466² = 1

8 0

3 years ago

How do you answer this pls help 7^2+4^3÷2^5

lana66690 [7]

Assignment: $\bold{Solve \ Equation: \ 7^2 \ + \ 4^3 \ \div 2^5}$

<><><><><><><>

Answer: $\boxed{\bold{51}}$

<><><><><><><>

Explanation: $\downarrow\downarrow\downarrow$

<><><><><><><>

[ Step One ] Apply PEMDAS Order Of Operations

Note: $\bold{PEMDAS: \ Parenthesis, \ Exponents, \ Multiply, \ Divide, \ Add, \ Subtract}$

$\bold{7^2: \ 49}$

[ Step Two ] Rewrite Equation

$\bold{49+64\div \:2^5}$

[ Step Three ] Calculate Exponents

$\bold{4^3: \ 64}$

[ Step Four ] Rewrite Equation

$\bold{49+64\div \:2^5}$

[ Step Five ] Calculate Exponents

$\bold{2^5: \ 32}$

[ Step Six ] Rewrite Equation

$\bold{49+64\div \:32}$

[ Step Seven ] Divide

$\bold{64\div \:32: \ 2}$

[ Step Eight ] Rewrite Equation

$\bold{49+2}$

[ Step Nine ] Add

$\bold{51}$

<><><><><><><>

$\bold{\rightarrow Mordancy \leftarrow}$

5 0

4 years ago

Read 2 more answers

An equilateral triangle has sides 8 units long. An equilateral triangle with sides 4 units long is cut off at the top, leaving a

Darina [25.2K]

Answer:

1:3

Step-by-step explanation:

Please study the diagram briefly to understand the concept.

First, we determine the height of the isosceles trapezoid using Pythagoras theorem.

$4^2=2^2+h^2\\h^2=16-4\\h^2=12\\h=\sqrt{12}\\ h=2\sqrt{3}$ units$

The two parallel sides of the trapezoid are 8 Inits and 4 units respectively.

Area of a trapezoid $=\dfrac12 (a+b)h$

Area of the trapezoid

$=\dfrac12 (8+4)*2\sqrt{3}\\=12\sqrt{3}$ Square Units$

For an equilateral triangle of side length s.

Area $=\dfrac{\sqrt{3}}{4}s^2$

Side Length of the smaller triangle, s= 4 Units

Therefore:

Area of the smaller triangle

$=\dfrac{\sqrt{3}}{4}*4^2\\=4\sqrt{3}$ Square units$

Therefore, the ratio of the area of the smaller triangle to the area of the trapezoid

$=4\sqrt{3}:12\sqrt{3}\\$Divide both sides by 4\sqrt{3}\\=1:3$

7 0

3 years ago

Simplify<br><br><br>5/8 m³ + 2 - 1.4 m³ =

creativ13 [48]

Answer:

-0.775m^3 + 2

3 0

3 years ago