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galina1969 [7]
3 years ago
8

George has a box of chocolates. There are 15 pieces of chocolate with nuts and 25 pieces of chocolate without nuts in the box. W

hat is the ratio of pieces of chocolate without nuts to pieces of chocolate with nuts?
Mathematics
2 answers:
nikdorinn [45]3 years ago
6 0

Answer:

5:3

Step-by-step explanation:

tekilochka [14]3 years ago
3 0

Answer:

5/3

Step-by-step explanation:

25/15 simplified to 5/3

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alina1380 [7]
A1 = 0.91
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sum = (0.91+-0.14) /2
sum = 2.31
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Liz earns a salary of $2,200 per month, plus a commission of 6% of her sales. she wants to earn at least $2,900 this month. ente
nlexa [21]
2200 + 0.06s > = 2900.....with s representing her total sales
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s > = 11666.67 <== her sales has to be at least this
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3 years ago
What is the value of z?
Licemer1 [7]

Answer:

z = 23 degrees

Step-by-step explanation:

Total degree inside a triangle = 180

We can add up the 2 angles we got.

62 + 95 = 157

Subtract 157 from 180.

180 - 157 = 23

Check = the angle missing is an acute angle (less than 90 degrees) and 23 is less than 90 degrees so it is possible.

I hope this helped and please mark me as brainliest!

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2 years ago
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The amount of protein that an individual must consume is different for every person. There are solid theoretical ideas that sugg
amid [387]

Answer:

The proportion of the population that have a protein requirement less than 0.60 g P • kg-1 • d-1 is 0.239, that is, 239 persons for every 1000, or simply 23.9% of them.

\\ 0.239 =\frac{239}{1000}\;or\;23.9\%

Step-by-step explanation:

From the question, we have the following information:

  • The distribution for protein requirement is <em>normally distributed</em>.
  • The population mean for protein requirement for adults is \\ \mu= 0.65 gP*kg^{-1}*d^{-1}
  • The population standard deviation is \\ \sigma =0.07 gP*kg^{-1}*d^{-1}

We have here that protein requirements in adults is normally distributed with defined parameters. The question is about <em>the proportion</em> <em>of the population</em> that has a requirement less than \\ x = 0.60 gP*kg^{-1}*d^{-1}.

For answering this, we need to calculate a <em>z-score</em> to obtain the probability of the value <em>x </em>in this distribution using a <em>standard normal table</em> available on the Internet or on any statistics book.

<h3>z-score</h3>

A z-score is expressed as

\\ z = \frac{x - \mu}{\sigma}

For the given parameters, we have:

\\ z = \frac{0.60 - 0.65}{0.07}

\\ z = \frac{0.60 - 0.65}{0.07}

\\ z = -0.7142857

<h3>Determining the probability</h3>

With this value for <em>z</em> at hand, we need to consult a standard normal table to determine what the probability of this value is.

The value for z = -0.7142857 is telling us that the requirement for protein is below the population mean (negative sign indicates this). However, most standard normal tables give a probability that a statistic is less than z and for values greater than the mean (in other words, positive values). To overcome this, we need to take the complement of the probability given for z-score z = 0.7142857, that is, subtract from 1 this probability, which is possible because the normal distribution is <em>symmetrical</em>.

Tables have values for <em>z</em> with two decimal places, then, for z = 0.7142857, we need to rewrite it as z = 0.71. For this value, the <em>standard normal table</em> gives a value of P(z<0.71) = 0.76115.

Therefore, the cumulative probability for values less than x = 0.60 which corresponds to a z-score = -0.7142857 is approximately:

\\ P(x

\\ P(x (rounding to three decimal places)

That is, the proportion of the population that have a protein requirement less than 0.60 g P • kg-1 • d-1 is

\\ 0.239 =\frac{239}{1000}\;or\;23.9\%

See the graph below. The shaded area is the region that represents the proportion asked in the question.

5 0
3 years ago
Find the derivative of f(x) = negative 11 divided by x at x = 9.
zavuch27 [327]
Remember the power rule
\frac{dy}{dx} x^m=mx^{m-1}
and the constant multipule rule
\frac{dy}{dx} cf(x)=c  \frac{dy}{dx} f(x) wher c is  a constant

so

f(x)= \frac{-11}{x} can be rewritten as
f(x)=-11x^{-1}
take deritivitve ad apply constnat multipule and power rule
f'(x)=-11(-1x^{-2})
f'(x)=11(x^{-2})
f'(x)= \frac{11}{x^2}

at x=9

f'(9)= \frac{11}{9^2}
f'(9)= \frac{11}{81}
4 0
3 years ago
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