Answer:
x^2 + y^2 <= 4, 0 <= z <= 8
Step-by-step explanation:
Combining 1 and 2, we get
0<=Z<=8
If we want disk of radius 2 in x-y plane to be centered at origin the inequality becomes:
x^2 + y^2 <= 4
4x²+3x-7 is the answer
=(4x²-2x)+(5x-7)
opening brackets
=4x²-2x+5x-7
=4x²+3x-7
i hope this will help you :)
Answer: So, 8%3 = 2
3,1
(3+6)= 9
times 1 would also be 9.
