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mart [117]
3 years ago
13

Write inequalites to describe the region. The solid cylinder that lies on or below the z=8 and or above the disk in the xy-plane

with center the origin and radius 2
Mathematics
1 answer:
Vladimir79 [104]3 years ago
8 0

Answer:

x^2 + y^2 <= 4, 0 <= z <= 8

Step-by-step explanation:

  1. Region that lies on/below the plane means Z<=8
  2. Region that lies on/above the xy plane means Z>=0.

Combining 1 and 2, we get

0<=Z<=8

If we want disk  of radius 2 in x-y plane to be centered at origin the inequality becomes:

x^2 + y^2 <= 4

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Step-by-step explanation:

We are given that there are 10 employees in a particular division of a company and their salaries have a mean of $70,000, a median of $55,000, and a standard deviation of $20,000.

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     Original Mean = $70,000

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b) Median will not get affected as median is the middle most value in the data set and since $1,000,000 is considered to be an outlier so median remain unchanged at $55,000 .

c) Original Variance = 20000^{2} i.e.  20000^{2} = \frac{\sum x^{2} - n*xbar }{n -1}

    Original \sum x^{2} = (20000^{2} * (10-1)) + (10 * 70,000) = $3,600,700,000

    New \sum x^{2} = $3,600,700,000 - 100,000^{2} + 1,000,000^{2} = 9.936007 * 10^{11}  

    New Variance = \frac{new\sum x^{2} - n*new xbar }{n -1} = \frac{9.936007 *10^{11}  - 10*160000 }{10 -1} = 1.103999 * 10^{11}    Therefore, standard deviation after change = \sqrt{1.103999 * 10^{11} } = $332264.804 .

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