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Andrei [34K]
2 years ago
13

20 ounces into pounds'

Mathematics
2 answers:
evablogger [386]2 years ago
7 0

Answer:

1.25

Step-by-step explanation:

20 ounces would be 1.25 pounds.

Please mark as brainliest! Thanks! If you need anymore help just let me know! :)

skad [1K]2 years ago
7 0

For this case we must perform a conversion. By definition we have to:

1 pound equals 16 ounces.

Thus, making a rule of three we have:

1lb -------------> 16oz

x ----------------> 20oz

Where "x" represents the amount of pounds equivalent to 20 ounces.

x = \frac {20 * 1} {16}\\x = 1.25

Finally we have 20 ounces equal to 1.25 pounds.

Answer:

20 ounces equals 1.25 pounds.

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Help find out what the x is please
miss Akunina [59]

Answer:

x=4

Step-by-step explanation:

First you want to add 8.8 to 7.2 and get 16 because you want to get x alone

Next divide divide 4x on both sides so 4x/4x cross out and left with just x. 16/4 =4

x=4

Hope this helps!


6 0
3 years ago
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Help me plz I need this quick
Lena [83]

I think it will be neither.

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3 years ago
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Need help Asap thank you in advance
julia-pushkina [17]

Answer:

12x^4-20x^2+32x=4x(3x^3-5x+8)

Step-by-step explanation:

<u>Common Factors</u>

An algebraic expression that is formed by sums or subtractions of terms can be factored provided there are numeric or variable common factors in all the terms.

The following expression

Z=12x^4-20x^2+32x

Can be factored in the constants and in the variable x.

1. To find the common factor of the variable, we must locate if the variable is present in all terms. If so, we take the common factor as the variable with an exponent which is the lowest of all the exponents found throughout the different terms. In this case, the lowest exponent is x (exponent 1).

2. To find the common factors of the constants, we take all the coefficients:

12 - 20 - 32

and find the greatest common divisor of them, i.e. the greatest number all the given numbers can be divided by. This number is 4, since 12/4=3, 20/4=5 and 32/4=8

3. The factored expression is

Z=12x^4-20x^2+32x=4x(3x^3-5x+8)

\boxed{12x^4-20x^2+32x=4x(3x^3-5x+8)}

3 0
3 years ago
Select the correct product.<br><br> (x 2 + 4x + 8)(2x - 1)
marusya05 [52]

Answer:

\large\boxed{(x^2+4x+8)(2x-1)=2x^3+7x^2+12x-8}

Step-by-step explanation:

Use FOIL: <em>(a + b)(c + d) = ac + ad + bc + bd</em>

(x^2+4x+8)(2x-1)\\\\=(x^2)(2x)+(x^2)(-1)+(4x)(2x)+(4x)(-1)+(8)(2x)+(8)(-1)\\\\=2x^3-x^2+8x^2-4x+16x-8\qquad\text{combine like terms}\\\\=2x^3+(-x^2+8x^2)+(-4x+16x)-8\\\\=2x^3+7x^2+12x-8

7 0
3 years ago
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