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katrin [286]
3 years ago
15

Suppose you have 40 meters of fencing what is the greatest rectangular area that you can enclose

Mathematics
1 answer:
Gelneren [198K]3 years ago
8 0
It'd help if you could sketch this situation.  Note that the area of a rectangle is equal to the product of its width and length:  A = L W.

Consider the perimeter of this rectangular area.  It's P = 2 L + 2 W.  Note that P = 40 meters in this problem.

Thus, if we choose to use W as our independent variable, then P = 40 meters = 2 L + 2 W.  Let's express L in terms of W.  Divide both sides of the following equation by 2:  40 = 2 L + 2 W.  We get 20 = L + W.  Thus, L = 20 - w.

Then the area of the rectangle is  A = ( 20 - W)*W.

Multiply this out.  Your result will be a quadratic equation.  Graph this quadratic equation (in other words, graph the function that represents the area of the rectangle).  For which W value is the area at its maximum?  

Alternatively, find the vertex of this graph:  remember that the x- (or W-) coordinate  of the vertex is given by

W = -b/(2a), where a is the coefficient of W^2 an b is the coefficient of W in your quadratic equation.

Finally, substitute this value of W into your quadratic equation, to calculate the maximum area.
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Step-by-step explanation:

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Step-by-step explanation:

5P3 refers to the permutations of 5 items taken 3 at a time. To evaluate this, we use factorials as follows;

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Using this concept, the above expression can now be simplified as follows;

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3 years ago
Can you help me find the perimeter
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Answer:

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this is basically saying, since opposite sides are equal in a rectangle,

Perimeter = 5 + 5 + 6 + 6, so P = 22ft

Step-by-step explanation:

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