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seraphim [82]
4 years ago
9

Myra borrowed $1,500 at 12.5% interest for three months. How much

Mathematics
1 answer:
den301095 [7]4 years ago
3 0
Now, this is for 3 months, and we're assuming, I guess it doesn't really matter, but using simple interest.

now, 3 months is not even a year, there are 12 months in 1 year, so 3 months is 3/12 years, or 1/4.

\bf \qquad \textit{Simple Interest Earned}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$1500\\
r=rate\to 12.5\%\to \frac{12.5}{100}\to &0.125\\
t=years\to \frac{3}{12}\to &\frac{1}{4}
\end{cases}
\\\\\\
I=1500\cdot 0.125\cdot \cfrac{1}{4}\implies 46.875\approx 46.88
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3 years ago
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Let's examine the given function first:
f(x) = x^2 + 1    is the same as    f(x) = 1(x-0)^2 + 1.
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Let x=0 to find the y-intercept:  f(0)=0^2+1 = 1; y-int. is at (0,1) (which happens to be the vertex also)

Comparing f(x) = x^2 + 1 to y = x^2, we see that the only difference is that f(x) has a vertical offset of 1.  So:  Graph y=x^2.  Then translate the whole graph UP by 1 unit.  That's it.  Note (again) that the vertex will be at (0,1), and (0,1) is also the y-intercept.
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ira [324]

Using an exponential function, it is found that it takes 5.42 years for the car to halve in value.

<h3>What is an exponential function?</h3>

A decaying exponential function is modeled by:

A(t) = A(0)(1 - r)^t

In which:

  • A(0) is the initial value.
  • r is the decay rate, as a decimal.

In this problem, the car depreciates 12% a year in value, hence r = 0.12 and the equation is given by:

A(t) = A(0)(0.88)^t.

It halves in value at t years, for which A(t) = 0.5A(0), hence:

A(t) = A(0)(0.88)^t

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t\log{0.88} = \log{0.5}

t = \frac{\log{0.5}}{\log{0.88}}

t = 5.42.

It takes 5.42 years for the car to halve in value.

More can be learned about exponential functions at brainly.com/question/25537936

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