The answer to question 1 is 120 times. and the answer to question 2 is 60% probability.
hope this helps:)
Answer:
first of all, the graphs are so poorly plotted,even kn computer...
anyways,
since the blue one ending at x=5 on the x axis,
while actual log ends at x=0 this means
X=x-5
and since, log1=0 but it's 5 in blue graph,
the graph is moved up by 5
hence,
y=5+log(x-5)
Answer:
The time it takes for the cannonball to hit the ground is 6.49 seconds.
Step-by-step explanation:
You know that the height of the cannonball above the ground, h, in meters, in time, t, in seconds, is found by the function h(t) = -4.9t² + 30.5t + 8.4. You want to calculate the time it takes for the cannonball to hit the ground, that is, the time it takes for the bullet to reach zero height. So, being h(t) = 0 you have:
0 = -4.9t² + 30.5t + 8.4
To solve a quadratic function 0=a*x² + b*x +c, the expression is applied:

In this case, being a = -4.9, b =30.5 and c =8.4 you have:

Solving you get:
t1= -0.26 seconds and t2=6.49 seconds
Since time does not have a negative value, then <u><em>the time it takes for the cannonball to hit the ground is 6.49 seconds.</em></u>
Answer:
bro I don't know. I just need the points so I can keep getting answers. good luck tho I guess.