Which function has a vertex at the origin

Mathematics

1 answer:

Alex787 [66]3 years ago

5 0

$\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \stackrel{\textit{we'll use this one}}{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{}{ h},\stackrel{}{ k}) \\\\[-0.35em] ~\dotfill\\\\ f(x)=-x^2\implies y = -(x-\stackrel{h}{0})^2+\stackrel{k}{0}\qquad \qquad \stackrel{\textit{vertex}}{(0,0)}$

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astraxan [27]

<h3><u>Question:</u></h3>

Find the average rate of change of f(x) = 3(2)^x between x = 1 and x = 4

<h3><u>Answer:</u></h3>

The average rate of change is 14

<h3><u>Solution:</u></h3>

The rate of change is given by formula:

$\text { Average Rate }=\frac{f(b)-f(a)}{b-a}$