Which function has a vertex at the origin

Mathematics

1 answer:

Alex787 [66]2 years ago

5 0

$\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \stackrel{\textit{we'll use this one}}{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{}{ h},\stackrel{}{ k}) \\\\[-0.35em] ~\dotfill\\\\ f(x)=-x^2\implies y = -(x-\stackrel{h}{0})^2+\stackrel{k}{0}\qquad \qquad \stackrel{\textit{vertex}}{(0,0)}$

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First you want to find the circumference of the circle. Given the radius 5ft you can then multiply it by 2 to get the diameter to make the equation for circumference much easier. 2*5=10. the diameter is 10ft.

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With the 60 degree you have to know that a circle is a full 360 degrees. 60 is 1/6 of 360 in meaning the distance the weight at the end of the cord will move is 1/6 of the circumference of this circle. Therefore you need to do 1/6*31.4 which equals about 5.2.

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