Answer:
we cant answer if we dont see the problem
Step-by-step explanation:
The answer is A. Even though it have a positive 3, the horizontal shift is opposite of what it is
Answer:
y= -1/2 x + 1
Step-by-step explanation:
The line passes through point (0, 1) and is perpendicular to line with equation :
y=2x
Perpendicular lines are those that give -1 when the product of their slopes is calculated.
This means m₁ *m₂= -1
In this case, m₁=2, finding m₂ as;
m₁ * m₂ = -1
2 * m₂ = -1
m₂ = -1/2
Using point (0, 1),m₂ = -1/2, and imaginary line (x, y) then the equation of the line in slope-intercept form y= mx + b will be;
-1/2 = y-1/x-0
-1/2 x = y-1
1-1/2x = y
The equation will be ;
y= -1/2 x + 1
{tan(60) + tan(10)}/{1 - tan(60)*tan(10)} - {tan(60) - tan(10)}/{1 + tan(10)*tan(60)}
<span>ii) Taking LCM & simplifying with applying tan(60) = √3, the above simplifies to: </span>
<span>= 8*tan(10)/{1 - 3*tan²(10)} </span>
<span>iii) So tan(70) - tan(50) + tan(10) = 8*tan(10)/{1 - 3*tan²(10)} + tan(10) </span>
<span>= [8*tan(10) + tan(10) - 3*tan³(10)]/{1 - 3*tan²(10)} </span>
<span>= [9*tan(10) - 3*tan³(10)]/{1 - 3*tan²(10)} </span>
<span>= 3 [3*tan(10) - tan³(10)]/{1 - 3*tan²(10)} </span>
<span>= 3*tan(30) = 3*(1/√3) = √3 [Proved] </span>
<span>[Since tan(3A) = {3*tan(A) - tan³(A)}/{1 - 3*tan²(A)}, </span>
<span>{3*tan(10) - tan³(10)}/{1 - 3*tan²(10)} = tan(3*10) = tan(30)]</span>
Insert the point, (5,-2) with the slope of the line to figure out the equation. You can either use point-slope form, or plug it for for slope-intercept form.
Slope-intercept form:
-2 = -2(5) + b
-2 = -10 + b
Add 10 on both sides
8 = b
Thus,
y = -2x + 8
Answer is B
