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7nadin3 [17]
2 years ago
7

Which of the following graphs represent a function?

Mathematics
1 answer:
Gwar [14]2 years ago
4 0

Answer:

<em>a. Graph A and Graph C</em>

Step-by-step explanation:

Those were the only graphs that pass the vertical line test.

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ms olivieri’s class plays a game in teams each team has the same number of students the ratio of teams to players is 8:32 how ma
Bezzdna [24]

Answer:

32 students

Step-by-step explanation:

8 teams

32 students

7 0
3 years ago
A circle of radius of 4 inches has an arc length of 5.8 inches. Find the measure of the central angle.
kondor19780726 [428]
<h3>SOLUTION : </h3>

The radius of the circle is 4 inch and has an arc length of 5.8 inches . We know that if the central angle is 360° then the arc length is 2\pi r . Similarly when angle is theta ,

\implies Arc = radius \times \theta

Now substitute respective values , from the given data ,

\implies 5.8 inch = 4inch * \theta \\\\\implies 0.14 m = 0.1 * \theta \\\\\implies \boxed{\red{\theta \approx 1.4 \ rad }}

This is our required answer!

4 0
3 years ago
Please Help: 0.125r - 0.0625 + 0.25r = 0.25 + r
IRISSAK [1]

Answer:

r=0.5

Step-by-step explanation:

0.125r+0.25r-0.0625=0.25+r

0.375r-0.0625=0.25+r

0.375r-r=0.25+0.0625

-0.625r=0.3125

r=0.3125/0.625

r=0.5

7 0
3 years ago
The area of a square is 25/36 in.2 what is the length of it's side?
Lesechka [4]
Our hint here is the identity of the shape. It is mentioned that the shape is a square. By definition, a square is a two-dimensional with four sides having equal measures. The formula for its area is:

A = s², where s is the length of its side
Substituting the value of A,
25/36 in² = s²
s = √(25/36)
s = 5/6 inches or 0.833 inches
4 0
3 years ago
Find the area A of the polygon with the given vertices.
Natalija [7]

Answer:

A = 35 square units

Step-by-step explanation:

Formula to calculate the distance between two points (x_1,y_1) and (x_2,y_2) is,

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Length of the segment between A(2, 2) and B(9, 2) = \sqrt{(9-2)^2+(2-2)^2}

                                                                                     = 7 units

Length of the segment between B(9, 2) and C(9, -3) = \sqrt{(9-9)^2+(2+3)^2}

                                                                                       = 5 units

Length of the segment between C(9, -3) and D(2, -3) = \sqrt{(9-2)^2+(-3+3)^2}

                                                                                        = 7 units

Length of the segment between A(2, 2) and D(2, -3) = \sqrt{(2-2)^2+(2+3)^2}

                                                                                       = 5 units

Therefore, given polygon is a rectangle.

Area of the rectangle = length × width

                                    = 7 × 5

                                    = 35 square units

4 0
2 years ago
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