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Oksi-84 [34.3K]
3 years ago
8

Which statements describe the benefits of artificial reefs? Select three options.

Biology
2 answers:
Nimfa-mama [501]3 years ago
7 0

Answer:

They can attract marine organisms.

They can prevent beach erosion.

They can attract tourists to the area.

Explanation:

Ganezh [65]3 years ago
5 0

Answer:

A C E

Explanation:

Those are the answers on edge

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TOPIC 4: GENETIC INHERITANCE
Harrizon [31]

<em>A</em><em>n</em><em>s</em><em>w</em><em>e</em><em>r</em><em>:</em>

YY

<em>E</em><em>x</em><em>p</em><em>l</em><em>a</em><em>n</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em>:</em>

Y-purple while y-white

YY is the genotype of a pure breed purple flowered pea plant

Yy is the genotype of a heterozygous pea plant flower (purple is dominant over white)

yy is the genotype of a white flowered pea plant that is generally called as recessive

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3 years ago
Explain ATP in detail
Naddika [18.5K]

Answer:

Adenosine triphosphate, also known as ATP, is a molecule that carries energy within cells. It is the main energy currency of the cell, and it is an end product of the processes of photophosphorylation (adding a phosphate group to a molecule using energy from light), cellular respiration, and fermentation.

It is made up of the molecule adenosine (which itself is made up of adenine and a ribose sugar) and three phosphate groups. It is soluble in water and has a high energy content due to having two phosphoanhydride bonds connecting the three phosphate groups

 Its main function is to store energy within the cell. ... ATP hydrolysis is an exotermic reaction, releasing energy which is used by the cell.sphate groups.

6 0
3 years ago
Read 2 more answers
Cystic fibrosis (CF) is one of most common recessive disorders among Caucasians it affects 1 in 1,700 newborns. What is the expe
Phantasy [73]

Answer: The expected frequency of carriers is P(Aa)=0.046.

The proportion of childs with CF is P(aa)=0.024.

25% of having a child with CF (aa).

Explanation:

Hardy-Weinberg's principle states that in a large enough population, in which mating occurs randomly and which is not subject to mutation, selection or migration, gene and genotype frequencies remain constant from one generation to the next one, once a state of equilibrium has been reached which in autosomal loci is reached after one generation. So, a population is said to be in balance when the alleles in polymorphic systems maintain their frequency in the population over generations.

Given the gene allele frequencies in the gene pool of a population, it is possible to calculate the expected frequencies of the progeny's genotypes and phenotypes. <u>If P = percentage of the allele A (dominant) and q = percentage of the allele a (recessive)</u>, the checkerboard method can be used to produce all possible random combinations of these gametes.

Note that p + q = 1, that is, the percentages of gametes A and a must equal 100% to include all gametes in the gene pool.

The genotypic frequencies added together should also equal 1 or 100%, and all the equations can be summarized as follows:

p+q=1\\(p+q)^{2}  = p^{2} +2pq+q^{2} = 1\\P(AA)=p^{2} \\P(aa)=q^{2} \\P(Aa)=2pq1

So, there are 1700 individuals and only one is affected. Since it is a recessive disorder, the genotype of that individual must be aa. So the genotypic frequency of aa is 1/1700=0.000588.

Then, P(aa)=q^{2}=0.000588. And with that we can calculate the value of q,

P(a)=q=\sqrt{0.000588}=0.024

And since we know that p+q=1, we can find out the value of p.

p+0.024=1\\1-0.024=p\\p=0.976

Next, we find out the genotypic frequency of the genotype AA:

P(A)=p=0.976\\P(AA)=p^{2} = 0.976^{2}=0.95

Now, we can find out the genotypic frequency of the genotype Aa:

P(Aa)=2pq=2 x 0.976 x 0.024 = 0.046

Notice than:

p^{2} + 2pq + q^{2} = 1\\x^{2} 0.976^{2} + 2 x 0.976 x 0.024 + 0.024^{2} = 1

Then, the expected frequency of carriers is P(Aa)=0.046

The proportion of childs with CF is P(aa)=0.024

If two parents are carriers, then their genotypes are Aa.

Gametes produced by them can only have one allele of the gene. So they can either produce A gametes, or a gametes.

In the punnett square, we can see that there genotypic ratio is 2:1:1 and the phenotypic ratio is 3:1. So, there is a probability of 25% of having an unaffected child, with both normal alleles (AA); 50% of having a carrier child (Aa) and 25% (0.25) of having a child with CF (aa).

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3 years ago
Identify the category each belongs to, based on the food it consumes ​
Stella [2.4K]

Answer:

pls the lightening is not good, I can only see the image of a leopard and an antelope

Explanation:

definitely a leopard carnivore and an antelope are herbivores animals (even though some may eat birds and small meats)

Hope this helps

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2 years ago
Which of the following tools should a scientist use to measure an object in meters.
Mekhanik [1.2K]

Answer:

C. Tape Measure

Explanation:

Thats the best of the options.

6 0
3 years ago
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