I don't know 1 but 2 can be 2.3 over 4.5 I think sorry if it's wrong but I hope it helps
To prove that jill is wrong we just need an example of this;
2*3*5*7*11*13 = 30030 (this is the smallest number with 6 different prime numbers)
5953*5981*5987 = 2.13x10^11 (which is obviously a much bigger number)
this is enough to prove that jill is wrong
Answer: left 7 units, up 4 units, and vertical compression
Step-by-step explanation:
Given
The function is 
First shift it to the left by 7 units, so the function becomes

Now compress it to make it one-third

Now, sift the graph upward by 4 units

Thus , the conditions are left 7 units, up 4 units, and vertical compression.
11 < square root of 85 because that is 9.219...
~JZ
-16t^2 + 25t + 8 = 10
-16t^2 + 25t - 2 = 0
t = 1.48 seconds