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4 years ago

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h(n)=-13nh(n)=−13nh, left parenthesis, n, right parenthesis, equals, minus, 13, n Complete the recursive formula of h(n)h(n)h, l

eft parenthesis, n, right parenthesis

1 answer:

mr Goodwill [35]4 years ago

5 0

Answer:

h(1)=-13

$h(n)=h(n-1)-13, n\geq 2$

Step-by-step explanation:

We are given that

$h(n)=-13n$

We have to find the recursive formula of h(n).

Substitute n=1

$h(1)=-13$

n=2

$h(2)=-13-13=-26=h(1)-13$

n=3

$h(3)=-13(3)=-39=-26-13=h(2)-13$

$h(4)=-13(4)=-52=-39-13=h(3)-13$

:

:

:

$h(n)=h(n-1)-13$

Therefore, the recursive formula is given by

h(1)=-13

$h(n)=h(n-1)-13, n\geq 2$

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AnnZ [28]

Answer:

A: $6x^2(x^8-16)$

B: $6x^2(x^4+4)(x^2+2)(x^2-2)$

Step-by-step explanation:

<u>A:</u>

Our expression is $6x^{10}-96x^2$ . We need to find some common factors. Clearly, we can see that both terms share the x² part, so we can definitely take that out:

$6x^{10}-96x^2$

$x^2(6x^8-96)$

Let's see if 96 is divisible by 6:

96 ÷ 6 = 16; since there's no remainder / the remainder is 0, we know 96 is divisible by 6, so we can also factor out 6:

$x^2(6x^8-96)$

$6x^2(x^8-16)$

Thus, the answer to part A is $6x^2(x^8-16)$ .

<u>B:</u>

Look at the $x^8-16$ part of the above factored expression. Notice that it is a difference of squares (because $x^8=(x^4)^2$ and 16 = 4²), so we can write this as:

$x^8-16$

$(x^4+4)(x^4-4)$

Now take a look at the $(x^4-4)$ part. Again, it's a difference of squares because $x^4=(x^2)^2$ and 4 = 2², so rewrite that as:

$x^4-4$

$(x^2+2)(x^2-2)$

Put it all together:

$6x^2(x^4+4)(x^2+2)(x^2-2)$

Thus, the answer to part B is $6x^2(x^4+4)(x^2+2)(x^2-2)$ .

6 0

3 years ago

Perform the indicated operation 5/11 + 9/11

Leni [432]

Answer:

It would be 14/11

when you make it a mixed number, it'll be 1 3/11

Step-by-step explanation:

You can't simplify it more than 3/11 so

1 3/11

8 0

3 years ago

Use only the digits 0 - 9 and the decimal and the negative sign, if needed, to fill in the blank.

saul85 [17]

Answer:

see below

Step-by-step explanation:

f(x) = 2x + 9,

Let x = -1

f(-1) = 2(-1) +9

= -2 +9

= 7

4 0

3 years ago

Read 2 more answers

Current government spending to fund public schools is about 6×1011 dollars per year. The average cost nationally for a student t

NeX [460]

60000000 students can attend public schools with the current funding

<em><u>Solution:</u></em>

Given that Current government spending to fund public schools is about $6 \times 10^{11}$ dollars per year

The average cost nationally for a student to attend a public school for a year is about $10,000

To find: number of students can attend public schools with the current funding

$\text{ current funding } = 6 \times 10^{11} \text{ dollars}$

$\text{ average cost for 1 student } = 10000 \text{ dollars }$

Therefore,

$\text{ number of students } = \frac{\text{ current funding }}{\text{ average cost of 1 student}}$

Substituting the values we get,

$\text{ number of students } = \frac{6 \times 10^{11}}{10000}\\\\\rightarrow \frac{6 \times 10^{11}}{10000} = \frac{6 \times 10^{11}}{10^4}\\\\\rightarrow \frac{6 \times 10^{11}}{10^4} = 6 \times 10^{11-4} = 6 \times 10^7\\\\\rightarrow 6 \times 10^7 = 60000000$

Thus 60000000 students can attend public schools with the current funding

6 0

3 years ago

A company is planning to set up a new manufacturing plant for giant inflatable beach balls and believe the costs follow a linear

Jet001 [13]

The cost(y) of producing x number of balls is given by the linear model y = 3.25x + 685000

Linear equation

A linear equation is in the form:

y = mx + b

where y, x are variables, m is the rate of change (slope) and b is the y intercept.

Let y represent the cost of producing x number of beach balls.

Using the point (10000, 587500) and (50000, 717500):

$y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-717500=\frac{717500-587500}{50000-10000} (x-10000)\\\\y=3.25x+685000$

The cost(y) of producing x number of balls is given by the linear model y = 3.25x + 685000

Find out more on Linear equation at: brainly.com/question/14323743

8 0

2 years ago