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valina [46]
4 years ago
15

for a button to fit through its buttonhole, the hole needs to be the size of the button diameter. What size buttonhole is needed

for a button with a cIrcumference of 7.3 centimeters? Use the value of 3. 14 to represent pi
Mathematics
1 answer:
postnew [5]4 years ago
8 0
If C is circumference, then C=2πr, where r is radius. Plug in 7.3 as C and solve for r. This leaves you with 3.65π. However, radius is only half of the diameter. To obtain the amount needed, one multiplies it by 2, which is 7.3π. That is your answer.
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Find The Missing Angle Measure <br>A. 34 <br>B. 90<br>C. 6<br>D. 23<br>please help me with this ​
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A researcher wishes to conduct a study of the color preferences of new car buyers. Suppose that 50% of this population prefers t
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Answer:

The probability that more than a third of the buyers would prefer brown is 0.8491.

Step-by-step explanation:

This is binomial problem with n=15 and p=0.50.

The binomial formula of probaility is:

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More than a third of the buyers: 15÷3=5

We have to find P(x>5).

P(x>5) = 1 - P(x≤5) = 1 - P(x=0) - P(x=1) - P(x=2) - P(x=3) - P(x=4) - P(x=5)

P(x=0)=\frac{15!}{0!15!} (0.5)^{0} (1-0.5)^{15}=0.00003

P(x=1)=\frac{15!}{1!14!} (0.5)^{1} (1-0.5)^{14}=0.00046

P(x=2)=\frac{15!}{2!13!} (0.5)^{2} (1-0.5)^{13}=0.00320

P(x=3)=\frac{15!}{3!12!} (0.5)^{3} (1-0.5)^{12}=0.01389

P(x=4)=\frac{15!}{4!11!} (0.5)^{4} (1-0.5)^{11}=0.04165

P(x=5)=\frac{15!}{5!10!} (0.5)^{5} (1-0.5)^{10}=0.09164

P(x>5) = 1 - P(x≤5)= 1- 0.00003 - 0.00046 - 0.00320 - 0.01389 - 0.04165 - 0.09164 = 0.8491

4 0
3 years ago
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