All categories

4 years ago

Mrs. Nguyen used 1.48 meters of netting to make 4 identical mini hockey goals. How much netting did she use per goal?

Mathematics

1 answer:

snow_tiger [21]4 years ago

8 0

0.37 meters of netting

<h3>Further explanation</h3>

<u>Given:</u>

Mrs. Nguyen used 1.48 meters of netting to make 4 identical mini hockey goals.

<u>Question:</u>

How much netting did she use per goal?

<u>The Process:</u>

We will solve the problem of conversion or in other words the ratio or proportion.

Option A: the conversion

Mrs. Nguyen used 1.48 meters of netting to make 4 identical mini hockey goals.

Then for every 1 goal, she needs 0.37 meters of netting.

Because $\boxed{ \ 1 \ goal \times \frac{1.48 \ meters}{4 \ goals} = 0.37 \ meters \ of \ netting.}$

Option B: the ratio (or proportion)

In the ratio, we process as follows:

$\boxed{ \ 4 \ goals : 1.48 \ meters \ of \ netting \ }$

Both are divided by 4.

$\boxed{ \ 1 \ goals : 0.37 \ meters \ of \ netting \ }$

Thus, she uses 0.37 meters of netting per goal.

Alternative problem

How much netting did she use for 8 goals?

$\boxed{ \ 8 \ goal \times \frac{1.48 \ meters}{4 \ goals} = \ ? \ }$ meters of netting.

We cross out eight and four because they can be divided.

$\boxed{ \ 2 \times 1.48 \ meters = 2.96 \ meters \ of \ netting. \ }$

She uses 2.96 meters of netting to make 8 identical mini hockey goals.

<h3>Learn more</h3>

About the engine displacement of Kawasaki Ninja brainly.com/question/5009365
The clothing maker brainly.com/question/1594110
The unit conversion brainly.com/question/5416146

Keywords: Mrs. Nguyen, 1.48 meters of netting, to make 4 identical mini hockey goals, how much netting, she uses per goal, conversion, the ratio, proportion

You might be interested in

-1/7 is greater than all of the follwing except

sergejj [24]

Answer:

0.1 is -1/10 which is obviously less than -1/7 .

Else we can also know by multiplying by 100

-1/10 *100 = -10

-1/7 *100 = -14.444

5 0

3 years ago

3. Let U and V be subspaces of a vector space W. Prove that their intersection UnV is also a subspace of W

kenny6666 [7]

Answer: The proof is done below.

Step-by-step explanation: Given that U and V are subspaces of a vector space W.

We are to prove that the intersection U ∩ V is also a subspace of W.

(a) Since U and V are subspaces of the vector space W, so we must have

0 ∈ U and 0 ∈ V.

Then, 0 ∈ U ∩ V.

That is, zero vector is in the intersection of U and V.

(b) Now, let x, y ∈ U ∩ V.

This implies that x ∈ U, x ∈ V, y ∈ U and y ∈ V.

Since U and V are subspaces of U and V, so we get

x + y ∈ U and x + y ∈ V.

This implies that x + y ∈ U ∩ V.

(c) Also, for a ∈ R (a real number), we have

ax ∈ U and ax ∈ V (since U and V are subspaces of W).

So, ax ∈ U∩ V.

Therefore, 0 ∈ U ∩ V and for x, y ∈ U ∩ V, a ∈ R, we have

x + y and ax ∈ U ∩ V.

Thus, U ∩ V is also a subspace of W.

Hence proved.

7 0

3 years ago

1. According to a recent survey, 13 out of the 33 students in a class take the bus to school. What is the ratio of students who

AlexFokin [52]

Answer: (1) 13/20 (2) 8 (3) Yes. They are proportional

<u>Step-by-step explanation:</u>

(1) 13 students take the bus.

33 - 13 = 20 students do not take the bus

$\dfrac{\text{take the bus}}{\text{do not take the bus}}:\dfrac{13}{20}$

(2)

$\dfrac{2\ red}{3\ green}=\dfrac{x}{12\ green}\\\\\\\underline{\text{cross multiply}:}\\2(12)=3(x)\\24=3x\\8=x$

(3)

$\dfrac{6}{10}\div \dfrac{2}{2}\quad =\dfrac{3}{5}\\\\\\\dfrac{9}{15}\div \dfrac{3}{3}\quad =\dfrac{3}{5}\\\\\\\dfrac{15}{25}\div \dfrac{5}{5}\quad =\dfrac{3}{5}$