Answer:
8
y
4
+
2
x
2
−
5
x
y
Step-by-step explanation:
Answer:
18
Step-by-step explanation:
1/3 * 18 = 6 or 6/(1/3) = 18 or 6 * 3 =18
Question # 14
Given the numbers
10 11 12 13 14 15 16 17 18 19 20
Let 'x' be the number
The condition breakdown:
I am less than 20.
- So the number 'x' must be less than 20 i.e. x < 20
I am more than 13.
- So the number 'x' must be greater than 13 i.e. x > 13
I am less than 17.
- So the number 'x' must be less than 17 i.e. x < 17
Finally:
I am 4 more than 12
i.e. 12+4 = 16
Thus, the number is x = 16
Question # 15
Part a)
Given the numbers
10 11 12 13 14 15 16 17 18 19 20
Let 'x' be the number
The condition breakdown:
I am more than 10.
I am less than 20.
I am more than 12.
I am less than 15.
As the numbers left after all the conditions are fulfilled are 13 and 14.
- But the last condition is, of the numbers that left, the number is greater than all the remaining numbers.
So, from the remaining number 13 and 14;
14 > 13
Thus, the number x = 14
Part b)
Drawing the number 14 in the place value:
Chart
Tens Ones
1 4
Answer:
There are 16 Oak tree in the forest.
Step-by-step explanation:
Given: There are 4 Oak tree on every 10 pine trees.
There are total 24 more pine tree than Oak tree.
Using the ratio of trees to find the number of trees.
Lets assume there are total number of Oak tree be "x".
∴ Total number of Pine trees will be 
We know the ratio of Oak to Pine tree is 4:10 or 
⇒
Multiplying both side by 
⇒ 
Using distributive property of multiplication, distributing 4 with x and 24.
⇒ 
Multiplying both side by 10
⇒ 
subtracting both side by 4x
⇒ 
dividing both side by 6
⇒
∴ 
Hence, There are 16 Oak trees in the forest.
X^2-22x-48=0
x^2-24x+2x-48=0
x(x-24)+2(x-24)
(x+2)(x-24)
Solve by grouping if you are able to find distinct factors that multiply to the last term and add to the middle term...this method is rather easy with easy to manage numbers. Complete the square if you cannot find distinct factors that multiply to the last term and add to the middle term. Completing the square helps when the equation is in the form of a parabola.