Answer:
Square.
Step-by-step explanation:
given J(-4,2) || K(0,3) || L(1,-1) || M(-3,-2)
given below the visual answer.
OR
you can find the distance of coordinate to coordinate:
Distance of JK
√(-4-0)² + (2-3)²
√17
Distance of KL
√(0-1)²+(3--1)²
√17
Distance of LM
√(1--3)²+(-1--2)²
√17
Distance of MJ
√(-3--4)²+(-2-2)²
√17
All sides are similar of √17 , so its a square.
By looking at the graph and seeing which point crosses the y axis. This point will always have an x coordinate of zero.
<em>Greetings from Brasil</em>
From radiciation properties:
![\large{A^{\frac{P}{Q}}=\sqrt[Q]{A^P}}](https://tex.z-dn.net/?f=%5Clarge%7BA%5E%7B%5Cfrac%7BP%7D%7BQ%7D%7D%3D%5Csqrt%5BQ%5D%7BA%5EP%7D%7D)
bringing to our problem
![\large{6^{\frac{1}{3}}=\sqrt[3]{6^1}}](https://tex.z-dn.net/?f=%5Clarge%7B6%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B6%5E1%7D%7D)
<h2>∛6</h2>
Answer:
5y-2xy
6q-6
Step-by-step explanation:
For the first expression, we can multiply 5 by y to get 5y. Thats all we can simplify it though, because xy is not equal to x or y.
For the second equation, we can easily add the variables to simplify. 6q-6
Hope this helps!
Answer:
Step-by-step explanation:
we know that
The density is equal to the mass divided by the volume
Let
x-----> the mass of marble
y----> the volume of marble
z----> the density of marble
in this problem we have
substitute and solve for x
