Answer:
The overall CGPA would be 2.90 so it is not possible for hum to secure a CGPA of 3 for graduation.
Step-by-step explanation:
Given,
CGPA = 2.75
Credit hours = 105
Last semester GPA = 4
Last semester credit hours = 15
CGPA = 
credit hours * gpa
in our case, it would be:
CGPA = 
=> 
=> 
=> 2.90
The overall CGPA would be 2.90 so it is not possible for hum to secure a CGPA of 3 for graduation.
Assuming both vertical lines are parallel and assuming I'm supposed to find all the unmarked angles...
Angle C:
Supplementary Angles.
x+36=180
180-36=x
x=144
Angle B:
Corresponding Angles.
Angle B ≅ Angle C
144
Angle A:
360 degrees in a quadrilateral
36+144+81+x=360
261+x=360
x = 99
<em>Hope it helps <3</em>
To effectively determine the correct answer, it would be helpful to write this into an algebraic expression. We let x as the number. We do as follows:
<span>Four times the square of a certain number increased by 6 times the number equals 108.
4x^2 + 6x = 108
The numbers can be either of the following since the equation generated was a quadratic equation which has two roots.
x = 4.5
x = -6 </span>
Answer:
14
Step-by-step explanation:
Order of operations rules require that we do any work inside parentheses first. Thus,
–(31 + 2) + 72 – (–5)^2
becomes:
-33 + 72 - 25, or
14
Important: Please use " ^ " to denote exponentiation; (-5)2 is incorrect, whereas (-5)^2 or (-5)² is correct.
Answer:
Yeah
Step-by-step explanation:
lol
