C major and A minor have no sharps or flats.
Answer:
By using the str() function.
teeth = 32
print(str(teeth))
Explanation:
The str() function returns the string version of the given object.
Virus.
A virus is a malicious program or script that Spreads.
Malware, however, will not spread.
Viruses can spread without a victim's permission because it is automated to do so.
For example, the Melissa virus would look like a file attachment that used reverse psychology to make you open it. From there, it goes through the first 50 email contacts stored on your computer and sends the virus to them from your computer.
Network technologies specialist Hannah would need to configure: C. RIP version 2 using Internet Protocol Version 4 (TCP/IPv4).
<h3>What is RIP?</h3>
RIP is an acronym for Routing Information Protocol and it can be defined as an intradomain routing protocol which is typically designed and developed based on distance vector routing.
<h3>The types of
RIP.</h3>
In Computer networking, there are two main types of Routing Information Protocol (RIP) and these include:
RIP version 2 are generally designed and developed to include subnet masks unlike RIP version 1. Thus, Hannah would need to configure RIP version 2 using Internet Protocol Version 4 (TCP/IPv4) allow several machines on different subnets to communicate with each other using broadcasts.
Read more on routing protocol here: brainly.com/question/24812743
Answer:
a) 4 processes
b) 2 resources
c) R1: 2 instances
R2: 2 instances
d) R2
e) R1
f) R1
g) No resource
h) R1
i) R2
j) R2
k) No
l)No deadlock
Explanation:
You need to know that the resources that are required by the processes for completion are shown by the request edge and the resources allocated are shown by the allocation edge. And thus, we can find what resources are allocated to the process, and required for the completion accordingly. And here again, the cycle is created, and hence deadlock may or may not occur. However, we see that resources have multiple instances and get freed on time. And hence, deadlock does not occur.
Like,
P4 uses R2 and free one instance of R2.
P3 then uses one instance of R2 and free R2.
P3 then uses one instance of R3 and free R3.
P1 uses one instance of R1 and free R1 one instance
P1 then uses R2 and free R2.
P2 uses R1 and free R1.
Hence, all the processes are complete and deadlock does not occur.
