Answer:
Use pelican, or similar heavy duty cases
Explanation:
Pelican is a brand btw. 10/10 would recommend
The output will be 10.
The while loop runs until numb is equal to or less than 13.
25 - 5 = 20
20 - 5 = 15
15 - 5 = 10, which is less than 13 so the loop stops and 10 is printed to the screen.
Answer: Program for bit stuffing in C
#include<stdio.h>
int main()
{
int i=0,count=0;
char data[50];
printf("Enter the Bits: ");
scanf("%s",data); //entering the bits ie. 0,1
printf("Data Bits Before Bit Stuffing:%s",databits);
printf("\nData Bits After Bit stuffing :");
for(i=0; i<strlen(data); i++)
{
if(data[i]=='1')
count++;
else
count=0;
printf("%c",data[i]);
if(count==4)
{
printf("0");
count=0;
}
}
return 0;
}
Explanation:
bit stuffing is the insertion of non-information bits during transmission of frames between sender and receiver. In the above program we are stuffing 0 bit after 4 consecutive 1's. So to count the number of 1's we have used a count variable. We have used a char array to store the data bits . We use a for loop to iterate through the data bits to stuff a 0 after 4 consecutive 1's.
Answer:
int k=0;
for(int i=0;i<=13; i++)
{
if (table[i].getKey().equals(key))
{
k=i;
}
else
{
continue;
}
}
V value= table[k].getValue();
return value;
}
Explanation:
Note table[i] is an entry, and we know the key as it is an argument input to the function. Hence, we find the entry position using the given key, and then find the corresponding value and return it. And this is what is required. There are 14 entries in this hashtable, as known from the question.
Its False, just took the test I chose true buh it told me I was wrong so iss gotta be false.
