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yan [13]
3 years ago
8

how do you call the squares method to compute the first five squares and store the result in an array numbers

Computers and Technology
1 answer:
IRINA_888 [86]3 years ago
8 0

Answer:

The method can be called using:

int[] returnarray = Squares();

<em>Where returnarray represents the name of the array</em>

Explanation:

To answer this, I will make an assumption that the Square method is an int array method (i.e. it returns array).

So, to call the method from main, an array has to be declared to get the values:

int[] returnarray = Squares();

Then an iteration is created to iterate through the array in order to print the array elements.

for (int i = 0; i < returnarray.length; i++)

 System.out.print(returnarray[i]+ " ");    

-------------------------------------------------------------------------------------------

The answer ends here

-------------------------------------------------------------------------------------------

As an addition, the complete program that includes the method and the main is:

<em>public class Main{</em>

<em> public static int [] Squares(){</em>

<em>     int [] arr = new int[5]; </em>

<em>     for(int i = 1;i<6;i++){</em>

<em>         arr[i-1] = i*i;</em>

<em>     }</em>

<em>     return arr;</em>

<em> }</em>

<em> public static void main(String[] args) {</em>

<em>  int[] returnarray = Squares();</em>

<em>  for (int i = 0; i < returnarray.length; i++)</em>

<em>  System.out.print(returnarray[i]+ " ");          </em>

<em> }  </em>

<em>}</em>

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Answer:

#include <iostream>

using namespace std;

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{

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   }

   while(c<6)//printing multiples.

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   int t,n;

   cin>>t;//How many times you want to check.

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Input:-

3

15

43

273

Output:-

First five multiples of 15 are : 3180 3195 3210 3225 3240  

First five multiples of 43 are : 3182 3225 3268 3311 3354  

First five multiples of 273 are : 3276 3549 3822 4095 4368

Explanation:

I have used a function to find the first five multiples of the of the numbers.The program can find the first five multiples of any integer between 3168 and 376020.In the function I have used while loop.First while loop is to find the first multiple of the integer n passed as an argument in the function.Then the next loop prints the first five multiples by just adding n to the first multiple.

In the main function t is for the number of times you want to print the multiples.In our case it is 3 Then input the integers whose multiples you want to find.

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see attachment for the step by step solution

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