Y = 2x² + 30x + 200
y = 2(x² + 15x + 100)
x² = x*x
100 ⇒ 1 x 100 ; 2 x 50 ; 4 x 25 ; 5 x 20 ; 10 x 10
200 = 2x² + 30x + 200
0 = 2x² + 30x + 200 - 200
0 = 2x² + 30x + 0
0 = 2(x² + 15x + ?)
<span>−5 ≤ x ≤ 20</span>
Answer:
111
Step-by-step explanation:
Please mark brainliest
Answer: 7824537630
Step-by-step explanation:
<span>Because the four numbers are consecutive, we can call the first one x, and the other three are x+1, x+2, and x+3, respectively.
x * (x+1) = (x+2) * (x+3) - 38
x^2 + x = x^2 + 5x +6-38
x^2 + x = x^2 + 5x - 32
-4x = -32
x=8
The four numbers are 8, 9, 10, and 11
check solution: 8*9=10*11-38
72=110-38
72=72</span>
