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pashok25 [27]
3 years ago
9

In class today I was really confused on this subject, I couldn't figure out how to do it! Maybe it's because I was tired or some

thing... anyway can you help me with the questions, and maybe explain to me how to do it? Thank you very much!!
Question:

Factor each binomial.
1. 9x+3

2. 12x-9

3. 45x^2+9x
Mathematics
2 answers:
ivolga24 [154]3 years ago
7 0

When you factor a number, you are writing the number as a product of two numbers. Usually (not always), the two numbers are smaller than the original and different from each other. For example, one way to factor 6 is to write it as 3*2 which says "3 times 2". Another example is to take a number like 32 and write it as 8*4.

The x is simply a placeholder for a number, so we can apply the same factoring rules to algebra as you've done in the past with regular numbers. Something like 9x is really a factorization of its own because it means 9 times x where x is some unknown number. If x were say x = 2, then 9x = 9*2 = 18.

We can rewrite 9x into 3*3x because 9 is the same as 3*3. The +3 at the end of 9x+3 can be turned into 3*1.

So we go from this: 9x+3

To this: 3*3x+3*1

At this point, it might seem like we're just complicating something just for the fun of it. In reality, we're helping ourselves to factor out a common term of 3. Use the distribution rule to go from 3*3x+3*1 to 3*(3x+1). If you were to distribute the outer 3 back into each term, then you'd get 3*3x+3*1 = 9x+3 again. So in a way, you can think of it as distribution but in reverse. Factoring pulls things apart while distribution puts it back together. That's possibly one way to remember it.

So in the end, 9x+3 completely factors to 3*(3x+1). Note how we have a product of two expressions 3 and 3x+1

This might seem like a lot of steps but it's not that bad. Once you have enough practice, you'll be able to do this in one or two steps fairly easily. I'll let you practice the others on your own. They are similar to problem 1. If you still are stuck, then let me know and I'll update the solution.

Alexeev081 [22]3 years ago
4 0

this is algrabra so what u do is first u need to know what x is also u can not add unlike term this is a lot so go to youtube and learn the faundaion cause i cant explian it so 9x +3 woul be eather if x is 2 then 9x2=18 then add 3


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Pls help me in this question
marshall27 [118]

Im so sorry that people these days are racist towards black people i just wish that people could protest not riot people are dying and and suffering i cant  believe that is alright not all white people are racist  and i just want peace in this world people losing there homes their cars their money i will not stand up for the rioting or the violince but i will not stand for racisim either srew every racist b**ch out there. please give me feedback i want to know your point of view

7 0
3 years ago
If A and B are two angles in standard position in Quadrant I, find cos( A +B ) for the given function values. sin A = 8/17 and c
horsena [70]

Answer:

Part 1) cos(A + B) = \frac{140}{221}

Part 2) cos(A - B) = \frac{153}{185}

Part 3) cos(A - B) = \frac{84}{85}

Part 4) cos(A + B) = -\frac{36}{85}

Part 5) cos(A - B) = \frac{63}{65}

Part 6) cos(A+ B) = -\frac{57}{185}

Step-by-step explanation:

<u><em>the complete answer in the attached document</em></u>

Part 1) we have

sin(A)=\frac{8}{17}

cos(B)=\frac{12}{13}

Determine cos (A+B)

we know that

cos(A + B) = cos(A) cos(B)-sin(A) sin(B)

step 1

Find the value of cos(A)

Remember that

cos^2(A)+sin^2(A)=1

substitute the given value

cos^2(A)+(\frac{8}{17})^2=1

cos^2(A)+\frac{64}{289}=1

cos^2(A)=1-\frac{64}{289}

cos^2(A)=\frac{225}{289}

cos(A)=\pm\frac{15}{17}

The angle A belong to the I quadrant, the cosine is positive

cos(A)=\frac{15}{17}

step 2

Find the value of sin(B)

Remember that

cos^2(B)+sin^2(B)=1

substitute the given value

sin^2(B)+(\frac{12}{13})^2=1

sin^2(B)+\frac{144}{169}=1

sin^2(B)=1-\frac{144}{169}

sin^2(B)=\frac{25}{169}

sin(B)=\pm\frac{25}{169}

The angle B belong to the I quadrant, the sine is positive

sin(B)=\frac{5}{13}

step 3

Find cos(A+B)

substitute in the formula

cos(A + B) = \frac{15}{17} \frac{12}{13}-\frac{8}{17}\frac{5}{13}

cos(A + B) = \frac{180}{221}-\frac{40}{221}

cos(A + B) = \frac{140}{221}

Part 2) we have

sin(A)=\frac{3}{5}

cos(B)=\frac{12}{37}

Determine cos (A-B)

we know that

cos(A - B) = cos(A) cos(B)+sin(A) sin(B)

step 1

Find the value of cos(A)

Remember that

cos^2(A)+sin^2(A)=1

substitute the given value

cos^2(A)+(\frac{3}{5})^2=1

cos^2(A)+\frac{9}{25}=1

cos^2(A)=1-\frac{9}{25}

cos^2(A)=\frac{16}{25}

cos(A)=\pm\frac{4}{5}

The angle A belong to the I quadrant, the cosine is positive

cos(A)=\frac{4}{5}

step 2

Find the value of sin(B)

Remember that

cos^2(B)+sin^2(B)=1

substitute the given value

sin^2(B)+(\frac{12}{37})^2=1

sin^2(B)+\frac{144}{1,369}=1

sin^2(B)=1-\frac{144}{1,369}

sin^2(B)=\frac{1,225}{1,369}

sin(B)=\pm\frac{35}{37}

The angle B belong to the I quadrant, the sine is positive

sin(B)=\frac{35}{37}

step 3

Find cos(A-B)

substitute in the formula

cos(A - B) = \frac{4}{5} \frac{12}{37}+\frac{3}{5} \frac{35}{37}

cos(A - B) = \frac{48}{185}+\frac{105}{185}

cos(A - B) = \frac{153}{185}

Part 3) we have

sin(A)=\frac{15}{17}

cos(B)=\frac{3}{5}

Determine cos (A-B)

we know that

cos(A - B) = cos(A) cos(B)+sin(A) sin(B)

step 1

Find the value of cos(A)

Remember that

cos^2(A)+sin^2(A)=1

substitute the given value

cos^2(A)+(\frac{15}{17})^2=1

cos^2(A)+\frac{225}{289}=1

cos^2(A)=1-\frac{225}{289}

cos^2(A)=\frac{64}{289}

cos(A)=\pm\frac{8}{17}

The angle A belong to the I quadrant, the cosine is positive

cos(A)=\frac{8}{17}

step 2

Find the value of sin(B)

Remember that

cos^2(B)+sin^2(B)=1

substitute the given value

sin^2(B)+(\frac{3}{5})^2=1

sin^2(B)+\frac{9}{25}=1

sin^2(B)=1-\frac{9}{25}

sin^2(B)=\frac{16}{25}

sin(B)=\pm\frac{4}{5}

The angle B belong to the I quadrant, the sine is positive

sin(B)=\frac{4}{5}

step 3

Find cos(A-B)

substitute in the formula

cos(A - B) = \frac{8}{17} \frac{3}{5}+\frac{15}{17} \frac{4}{5}

cos(A - B) = \frac{24}{85}+\frac{60}{85}

cos(A - B) = \frac{84}{85}

Part 4) we have

sin(A)=\frac{15}{17}        

cos(B)=\frac{3}{5}

Determine cos (A+B)

we know that    

cos(A + B) = cos(A) cos(B)-sin(A) sin(B)

step 1

Find the value of cos(A)

Remember that

cos^2(A)+sin^2(A)=1

substitute the given value

cos^2(A)+(\frac{15}{17})^2=1

cos^2(A)+\frac{225}{289}=1

cos^2(A)=1-\frac{225}{289}      

cos^2(A)=\frac{64}{289}

cos(A)=\pm\frac{8}{17}

The angle A belong to the I quadrant, the cosine is positive

cos(A)=\frac{8}{17}

step 2

Find the value of sin(B)

Remember that

cos^2(B)+sin^2(B)=1

substitute the given value

sin^2(B)+(\frac{3}{5})^2=1

sin^2(B)+\frac{9}{25}=1

sin^2(B)=1-\frac{9}{25}

sin^2(B)=\frac{16}{25}

sin(B)=\pm\frac{4}{5}

The angle B belong to the I quadrant, the sine is positive

sin(B)=\frac{4}{5}

step 3

Find cos(A+B)

substitute in the formula    

cos(A + B) = \frac{8}{17} \frac{3}{5}-\frac{15}{17} \frac{4}{5}

cos(A + B) = \frac{24}{85}-\frac{60}{85}

cos(A + B) = -\frac{36}{85}

Download odt
4 0
4 years ago
What is the volume of a cylinder tank with diameter of 50cm and height of 80cm
stepladder [879]

Answer:

12566.37061435917

or

4000π

Step-by-step explanation:

the equation is 50π×80

this is because you have to find the area of the circle which is diameter times pi and then you multiply that by the height of the cylinder

5 0
3 years ago
Write each decimal as a percent 0.34, 0.93, 0.57, 0.8
AVprozaik [17]
34%, 93%, 57%, and 80%.

All you do is move the decimal place two spaces to the right to turn a decimal into a percent.
7 0
3 years ago
If DH=4x-2 and FH=x+28, find the value of x for which DEFG must be a parallelogram.
Mnenie [13.5K]
Given that DH=4x-2 and FH=x+28, the value of x which will make DEFG a parallelogram will be given as follows;
4x-2=x+28
4x-x=28+2
3x=30
thus
x=30/3
x=10
The answer is C] 10
8 0
3 years ago
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