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Sedbober [7]
3 years ago
11

If 6 pears and 5 oranges cost $1.87 and 12 pears and 2 oranges cost $1.90, how much would 3 pears and 3 oranges cost?

Mathematics
1 answer:
Artyom0805 [142]3 years ago
4 0
I'm going to do elimination to find the price of one pear and one orange.
6p +5o =1.87
12p + 2o=1.90
I'm going to multiply the first equation by -2.
-12p-10o = -3.74
12p + 2o =1.90
-8o= -1.84
-1.84÷ -8= .23= o
12p + 2 (.23) = 1.90
12p + .46 = 1.90
12p = 1.44
p=.12
A pear equals .12, while an orange equals .23.
3×.12= .36
.23× 3 = .69
.69 + .36 = 1.05
It would cost $1.05.
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the diagonal length represent the hypotenuse side of each of the right angle, knowing the pythagoras theorem:

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dimaraw [331]

Answer:

Domain [-5,∞)

Range [0,∞)

Step-by-step explanation:

Part 1) Find the domain

we have

f(x)=\frac{1}{2}\sqrt{x+5}

we know that

The radicand must be greater than or equal to zero

so

x+5\geq 0

solve for x

subtract 5 both sides

x\geq -5

The solution for x is the interval [-5,∞)

All real numbers greater than or equal to -5

Remember that

The domain of a function is the set of all possible values of x

therefore

The domain of the function f(x) is the interval  [-5,∞)

Part 2) Find the range

we have

f(x)=\frac{1}{2}\sqrt{x+5}

Find the value of f(x) for the minimum value of x

For x=-5

f(x)=\frac{1}{2}\sqrt{-5+5}

f(x)=0

The minimum value of f(x) is equal to zero

so

The solution for f(x) is the interval [0,∞)

All real numbers greater than or equal to 0

Remember that

The range of a function is the complete set of all possible resulting values of y, after we have substituted the domain.

therefore

The range of the function is the interval [0,∞)

8 0
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