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2 years ago

Solve the following Simultaneous equationUsing any suitable method x+6y=2, 3x +2y =10

Mathematics

1 answer:

uranmaximum [27]2 years ago

5 0

Answer:

x = 0.5

y = -1/4 or -0.25

Step-by-step explanation:

x + 6y = 2

3x + 2y = 10

Multiply a number by any of the equations to get numbers of the same variable

3x + 18y = 6

3x + 2y = 10

3x - 3x = 0

NB: subtract evenly if u subtract down from top make sure u subtract down from top throughout

16y = -4

16y/16 = -4/16

y = -1/4 or -0.25

to find the x value, any where you see y u put in the y value(-0.25)

So u'll pick just one of the equations above

x + 6(0.25) = 2

x + 1.5 = 2

x = 1.5 + 2

x = 0.5

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What is the value of z, rounded to the nearest tenth? Use the law of sines to find the answer. 2. 7 units 3. 2 units 4. 5 units

worty [1.4K]

The law of sine is the nothing but the relationship between the sides of the triangle to the angle of the triangle (oblique triangle).

The value of the $z$ is 3.2 (rounded to the nearest tenth). The option 2 is the correct option.

The law of sine is the nothing but the relationship between the sides of the triangle to the angle of the triangle (oblique triangle).

It can be given as,

$\dfrac{\sin A}{a} =\dfrac{\sin B}{b} =\dfrac{\sin C}{c}$

Here $A,B,C$ are the angle of the triangle and $a,b,c$ are the sides of that triangle.

Given information-

The triangle for the given problem is attached below.

In the triangle the base of the triangle is 2.6 units long.

The sine law for the given triangle can be written as,

$\dfrac{\sin X}{x} =\dfrac{\sin Y}{y} =\dfrac{\sin Z}{z}$

As the value of $y$ side is known and the value of $z$ has to be find. Thus use

$\dfrac{\sin Y}{y} =\dfrac{\sin Z}{z}$

Put the values,

$\dfrac{\sin 51}{2.6} =\dfrac{\sin 76}{z}$

Solve it for the $z$ ,

$z=\dfrac{\sin 76\times 2.6}{\sin 51}\\z=3.2462$

Hence the value of the $z$ is 3.2 (rounded to the nearest tenth). The option 2 is the correct option.

Learn more about the sine law here;

brainly.com/question/2264443

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2 years ago

Look at the picture please!!!!

devlian [24]

Answer:

Angle 1: 131

Angle 6: 49

4 0

2 years ago

Read 2 more answers

HELP!!!<br> 31) Find the measure of line segment DF.<br> A) 12<br> B) 13<br> C) 14<br> D) 15

oksian1 [2.3K]

Step-by-step explanation:

for the relationship of lengths of internal chords the product of both segments of a chord is equal for all intersecting chords.

in our case

(x+8)×8 = 7×16 = 112

8x + 64 = 112

8x = 48

x = 6

so, D-F = x + 8 = 6 + 8 = 14

so, C is correct

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1 year ago

What is the answer to this?

tensa zangetsu [6.8K]

The answer is b!!!!!

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2 years ago

A representative from the National Football League's Marketing Division randomly selects people on a random street in Kansas Cit

Orlov [11]

Using the binomial distribution, we have that:

a) 0.1024 = 10.24% probability that the marketing representative must select 4 people to find one who attended the last home football game.

b) 0.2621 = 26.21% probability that the marketing representative must select more than 6 people to find one who attended the last home football game.

c) The expected number of people is 4, with a variance of 20.

For each person, there are only two possible outcomes. Either they attended a game, or they did not. The probability of a person attending a game is independent of any other person, which means that the binomial distribution is used.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

p is the probability of a success on a single trial.

n is the number of trials.

p is the probability of a success on a single trial.

The expected number of <u>trials before q successes</u> is given by:

$E = \frac{q(1-p)}{p}$

The variance is:

$V = \frac{q(1-p)}{p^2}$

In this problem, 0.2 probability of a finding a person who attended the last football game, thus $p = 0.2$ .

Item a:

None of the first three attended, which is P(X = 0) when n = 3.
Fourth attended, with 0.2 probability.

Thus:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{3,0}.(0.2)^{0}.(0.8)^{3} = 0.512$

$0.2(0.512) = 0.1024$

0.1024 = 10.24% probability that the marketing representative must select 4 people to find one who attended the last home football game.

Item b:

This is the probability that none of the first six went, which is P(X = 0) when n = 6.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{6,0}.(0.2)^{0}.(0.8)^{6} = 0.2621$

0.2621 = 26.21% probability that the marketing representative must select more than 6 people to find one who attended the last home football game.

Item c: