Question

Find the 100th term of the arithmetic sequence with first term 4 and eighth term 32.

Answer 1

Answer:400

Step-by-step explanation:

Given

First term a=4

and 4th term is 32

i.e.

$a_8=32$

let d be the common difference

a+7d=32

a=4

therefore

7d=32-4=28

d=4

Therefore 100 th term is

$a_{100}=a+99d=4+99\cdot 4=400$