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3 years ago

May someone help me SKSKSKSKSK

Mathematics

1 answer:

Arte-miy333 [17]3 years ago

3 0

Answer:

P= A + B + C

Step-by-step explanation:

P= Side + base + Side

P= 10 + 6 + 8

P = 24

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Given the speeds of each runner below, determine who runs the fastest. \text{Katie runs 10 feet per second.} Katie runs 10 feet

Mrrafil [7]

Answer:

noah

Step-by-step explanation:

katie = 10 f/s

ron = 466 f/33s

noah = 559 f/60s

katie = 10 f/s

ron = 466/33 = 14.1212...f/s

noah = 559/60 = 9.3166...f/s

noah is the fastest

4 0

3 years ago

Let f(x) = 5x^3 -2x and g(x) =3x^3. Find f(x) * g(x) & state the domain

Sedbober [7]

Answer:

f(x) × g(x) = 15x^6 - 6x^4

Step-by-step explanation:

hello :

f(x) = 5x^3 -2x and g(x) =3x^3.

f(x) × g(x) = 3x^3(5x^3 -2x) = 15x^6 - 6x^4

6 0

3 years ago

Abigail needs at least $199 to purchase the new phone that she wants. Last week she babysat and earned $45. Write and solve an i

N76 [4]

5 or 4 weeks because 199 divided by 45 equals 4.4222222222

7 0

4 years ago

– 42 – 54 + 96 = what is the answer

mart [117]

Answer:

Answer:the answer is zero 

Answer:the answer is zero Step-by-step explanation:

Answer:the answer is zero Step-by-step explanation:when we add -42 and -54 the answer we get is -96. -96and +96 cut each other and then the answer is zero 

 $- 42 - 54 + 96 = 0$ 

6 0

2 years ago

The amount of time, in minutes, that a woman must wait for a cab is uniformly distributed between zero and 12 minutes, inclusive

murzikaleks [220]

Answer:

$P(X\leq x) =\frac{x-a}{b-a}, a \leq x \leq b$

And using this formula we have this:

$P(X$

Then we can conclude that the probability that that a person waits fewer than 11 minutes is approximately 0.917

Step-by-step explanation:

Let X the random variable of interest that a woman must wait for a cab"the amount of time in minutes " and we know that the distribution for this random variable is given by:

$X \sim Unif (a=0, b =12)$

And we want to find the following probability:

$P(X$

And for this case we can use the cumulative distribution function given by:

$P(X\leq x) =\frac{x-a}{b-a}, a \leq x \leq b$

And using this formula we have this:

$P(X$

Then we can conclude that the probability that that a person waits fewer than 11 minutes is approximately 0.917

7 0

3 years ago