The 3rd option, x=75y=35.
Answer:
No.
If y is greater than 3, it is not a solution to the system of inequalities. (7,5) has a y value of 5, therefore it is is not a solution.
-6+3-3(-18)
Okay.
Work from left to right.
-6 plus 3 equals -3.
(Think of it as in a number line, from the spot of -6, move right three units. This will give you -3. Anyways..)
Now you have -3-3
The result is -6.
-6(-18)
Negative six times negative eighteen equals positive 108.
The answer is 108.
(Sorry for the long reply)
- Here the line is parallel to x axis
- Slope (m) will be tan(0)=0
- Y intercept is 1.
Y is constant.
The equation of line will be
I got D.
There's a few ways to solve it; I prefer using tables, but there are functions on a TI-84 that'll do it for you too. The logic here is, you have a standard normal distribution which means right away, the mean is 0 and the standard deviation is 1. This means you can use a Z table that helps you calculate the area beneath a normal curve for a range of values. Here, your two Z scores are -1.21 and .84. You might notice that this table doesn't account for negative values, but the cool thing about a normal distribution is that we can assume symmetry, so you can just look for 1.21 and call it good. The actual calculation here is:
1 - Z-score of 1.21 - Z-score .84 ... use the table or calculator
1 - .1131 - .2005 = .6864
Because this table calculates areas to the RIGHT of the mean, you have to play around with it a little to get the bit in the middle that your graph asks for. You subtract from 1 to make sure you're getting the area in the middle and not the area of the tails in this problem.