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rusak2 [61]
3 years ago
5

Town B is 40km due North of town A. what is the bearing of A from B​

Mathematics
1 answer:
marysya [2.9K]3 years ago
6 0

Answer:

Step-by-step explanation:

40km is the bearing

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Answer:

Sister Is a PIG

Step-by-step explanation:

and Your Friends Gets her Scraps

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The value of each variable
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This is a simple Pythagorean Theorem problem. 7 is the hypotenuse so you would do c^2-a^2=b^2. In this case 7^2-2^2=b^2. 7^2 is 49 and 2^2 is 4 so you have 49-4=b^2. 49-4 is 45. The square root of 45 is 6.70. So x=6.70
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3 years ago
If the endpoint is (-5,8) and the midpoint is (10,-9) what would the other endpoint be
netineya [11]

Answer:

thats a great question

Step-by-step explanation:

6 0
3 years ago
A humanities professor assigns letter grades on a test according to the following scheme. A: Top 12% of scores B: Scores below t
RUDIKE [14]

Answer:

The minimum score required for an A grade is 88.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 77.8, \sigma = 8.5

Find the minimum score required for an A grade.

Top 12%, which is at least the 100-12 = 88th percentile, which is the value of X when Z has a pvalue of 0.88. So it is X when Z = 1.175.

Z = \frac{X - \mu}{\sigma}

1.175 = \frac{X - 77.8}{8.5}

X - 77.8 = 1.175*8.5

X = 87.8

Rounding to the nearest whole number

The minimum score required for an A grade is 88.

5 0
3 years ago
Read 2 more answers
Tina loves to read. Before breakfast, she read 21/2 pages, at lunch she read 31⁄5 pages, and after dinner she read 11⁄3 pages. H
MrMuchimi

Answer: 7 1/30

Step-by-step explanation:

Tina loves to read. Before breakfast, she read 2 1/2 pages, at lunch she read 3 1/5 pages, and after dinner she read 1 1/3 pages. To find the total, we add all the pages together. This will be:

2 1/2 + 3 1/5 + 1 1/3

The LCM of 2, 5 and 3 is 30.

= 2 15/30 + 3 6/30 + 1 10/30

= 6 31/30

= 7 1/30.

5 0
3 years ago
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