Question

The sum of 4 consecutive integers is 130 what is the third number in the sequencePLZ HELP!!!

Answer 1

Answer:

$\huge\boxed{3rd\ number = 33}$

Step-by-step explanation:

Let the consecutive numbers(Coming one after another) be x, x+1, a+2 and x+3

So,

x+x+1+x+2+x+3 = 130

4x + 6 = 130

Subtracting 6 to both sides

4x = 130-6

4x = 124

Dividing both sides by 4

x = 32

So,

1st number = x = 31

2nd Number = x+1 = 31+1 = 32

3rd number = x+2 = 31+2 = 33

4th number = x+3 = 31+3 = 34

Answer 2

Answer:

33

Step-by-step explanation:

We can write an equation:

x+x+1+x+2+x+3=130

x represents the smallest number of the consecutive integers

By the way, an example of consecutive would be 2, 3, 4, 5 or 10, 11, 12, 13

We can combine like terms from our equation:

4x+6=130

4x=124

x=31

The smallest number is 31. The second number would be 31+1=32, which means the third number is 33!

Hope this helps! :) :)