There are eight students in a class. Only one of them has passed Exam P/1 and only one of them has passed Exam FM/2. No student
1 answer:
Answer: There is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.
Step-by-step explanation:
Total number of students = 8
Number of student who has passed Exam P/1 = 1
Number of student who has passed Exam FM/2 = 1
No student has passed more than one exam.
According to question, exactly three students from a randomly chose group of four students have not passed Exam P/1 or Exam FM/2.
So, Probability will be
Hence, there is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.
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Answer:
See attached worksheet.
Step-by-step explanation:
See attached worksheet for the table and graph.
I assume that "functation notation: simply means using x and y:
y = 2x + 3
The relationship between the number of T-shirts and cost is defined by y = 2t + 3, where:
y is the total cost,
x is the number of t-shirts,
the 2 is the cost for 1 t-shirt ($/t-shirt), and
3 is a one=time charge of $3 for each order.
The graph (attached) shows a straight line with a y-intercept of 3, the initial order fee. It is linear since the cost of a t-shirt remains the same egardless of order size.
