Answer:i cant see it that well
Step-by-step explanation:
we are given
position function as
we know that acceleration is second derivative of position
so, firstly, we will find first derivative
now, we can simplify it
now, we can find derivative again
now, we can plug t=2
and we get
so,
the value of the person’s acceleration a at t=2s is -4..........Answer
Find f(x+h) and f(x), and plug these values into the difference quotient formula.
6x + 3h
The slope would be calculated as m = (y2 -y1)/(x2-x1)
So plugging in it would be m = (10- (-4))/(6-2) = 3.5
Then plugging into point slope form which is y - y1 = m(x - x1)
You would get y - 10 = 3.5(x-6) which simplifies is
Y = 3.5x -11
Answer:
The tatal budget of what, there's no budget the budget down so I can do the problem.