Question

Keep the function x(t)=8∗t−2∗t∗t in the expression evaluator. what is the value of the person’s acceleration a at t=2s?

Answer 1

we are given

position function as

$x(t)=8t-2t^2$

we know that acceleration is second derivative of position

so, firstly, we will find first derivative

$x'(t)=8*1-2*2*t^1$

now, we can simplify it

$x'(t)=8-4t$

now, we can find derivative again

$x''(t)=0-4*1$

$x''(t)=-4$

now, we can plug t=2

and we get

$x''(2)=-4$

so,

the value of the person’s acceleration a at t=2s is -4..........Answer