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3 years ago

Awarding more points!!!!

Mathematics

1 answer:

dezoksy [38]3 years ago

8 0

a) t in this equation would be the number of years so in this case t=4

b)3.5/100=0.035

c)A=600(1+(0.035/1)^(1×4)=688.51

d) The account earned $88.51

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I’m once again asking for your Mathematical support!

Sergio [31]

Answer:

Step-by-step explanation:

let x= hamburger

let y= hot dogs

Jalen: 5x+3y=28.50

Victoria: 2x+6y=21

is second choice

5 0

2 years ago

How many solutions does the system have? <br> {2x+2y=8 <br> {3x+y=8 2x+2y=8

umka2103 [35]

Answer:

Step-by-step explanation:

first we put them in y = mx + b form...then we compare the slopes and the y int's. In y = mx + b form, the slope is in the m position and the y int is in the b position.

2x + 2y = 8

2y = -2x + 8

y = -x + 4......slope here is -1 and y int is 4

3x + y = 8

y = -3x + 8.....slope here is -3 and y int is 8

This system has 1 solution <===

================================

learn this...it helps

* if there are different slopes and different y int, then there is 1 solution

* if there are the same slopes and different y int, then there is no solutions because u have parallel lines

* if there are same slopes and same y int, there is infinite solutions because u have the same line

4 0

3 years ago

Read 2 more answers

Assume that the Poisson distribution applies to the number of births at a particular hospital during a randomly selected day. As

kakasveta [241]

Answer:

0.9999985 = 99.99985% probability that in a day, there will be at least 1 birth.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Assume that the mean number of births per day at this hospital is 13.4224.

This means that $\mu = 13.4224$

Find the probability that in a day, there will be at least 1 birth.

This is:

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-13.4224}*13.4224^{0}}{(0)!} = 0.0000015$

Then

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0000015 = 0.9999985
$

0.9999985 = 99.99985% probability that in a day, there will be at least 1 birth.

7 0

3 years ago

Callie bought a bag of dried fruit: cherries, pears, and apples.In the bag,1/4 of the dried fruit is cherries and 2/3 of the rem

goldenfox [79]

Answer:

There 24 pieces of Apples in the bag of dry fruit.

Step-by-step explanation:

Let the total number of dried fruit bought be 'x'.

Given:

1/4 of the dried fruit is cherries.

Hence Number of cherries = $\frac{1}{4}x$

Also Given:

2/3 of the remainder is pears.

Hence we can say Number of pears is equal to 2/3 times Total number of dried fruit minus Number of cherries.

Framing the equation we get;

Number of Pears = $\frac{2}{3} (x-\frac{1}{4}x) = \frac{2}{3} x- \frac{2}{12}x= \frac{2}{3} x- \frac{1}{6}x$

But Given:

Number of Pears = 48

Substituting the values we get;

$\frac{2}{3} x- \frac{1}{6}x= 48\\$

By taking L.C.M we get;

$\frac{2\times2}{3\times 2} x- \frac{1\times1}{6\times1}x= 48\\\\\frac{4}{6} x- \frac{1}{6}x= 48\\\\\frac{4x-x}{6}=48\\\\\frac{3x}{6}=48\\\\\frac{x}{2}=48\\\\x= 48\times2= 96$

Hence Total Number of Dry fruit = 96 pieces.

Number of cherries = $\frac{1}{4}x=\frac{1}{4} \times 96 = 24$

Now We need to find the Number of Pieces of Apples.

We know that Total Number of Pieces of dried fruit is equal to sum of Number of cherries and Number of Pears and Number of Apples.

Framing Equation we get

Number of Pieces of Apples= Total Number of Pieces of dried fruit - Number of cherries - Number of Pears = 96-48-24 =24 pieces

Hence There 24 pieces of Apples in the bag of dry fruit.

5 0

3 years ago

What is the 15th term in the sequence with the given formula?<br> An = 7n – 10

zhenek [66]

15th term :
7.15-10 = 105-10 = 95 good luck

8 0

3 years ago