Potential energy<span> is the </span>energy<span> possessed by an object because of its position.
So it is D the highest point of the trajectory. </span>

k and m must satisfy 8k = 1 mean k = ⅛
and 2km+⅝=0 mean m = -5/2
X would be less than 6 2/3.
Answer:
87.92
Step-by-step explanation:
you have to multiply 3.14 by 2 which will give you 6.28, then you multiply 6.28 by 14 which gives you 87.92. hope this helps
Given:
The growth of a sample of bacteria can be modeled by the function

where, b is the number of bacteria and t is time in hours.
To find:
The number of total bacteria after 3 hours.
Solution:
We have,

Here, b(t) number of total bacteria after t hours.
Substitute t=3 in the given function, to find the number of total bacteria after 3 hours.



Therefore, the number of total bacteria after 3 hours is 119.1016.