We have been given that in ΔHIJ, the measure of ∠J=90°, the measure of ∠I=29°, and JH = 88 feet. We are asked to find the length of IJ to the nearest tenth of a foot.
First of all, we will draw a right triangle using our given information as shown in the attachment.
We can see that in triangle HIJ, the side IJ is adjacent side to angle I and JH is opposite side to angle I.
We know that tangent relates opposite side of right triangle to adjacent side.
Upon rounding to nearest tenth, we will get:
Therefore, the length of the side IJ is approximately 258.8 units.
Equation 1) y = x² + 10x + 11
Equation 2) y = x² + x - 7
Subtract equations from one another.
9x = 18
Divide both sides by 9.
x = 2
Plug in 2 for x in the first equation.
y = x² + 10x + 11
y = 2² + 10(2) + 11
Simplify.
y = 4 + 20 + 11
y = 35
Plug in 35 for y and 2 for x in the first equation to check your work.
y = x² + 10x + 11
35 = 2² + 10(2) + 11
35 = 4 + 20 + 11
35 = 24 + 11
35 = 35
So, we know that our answer is correct! :))
x = 2, y = 35
The sample is 200 randomly selected students.
The following things should be considered:
- Let us assume the no of siblings for each student be x.
- Now for determining the mean no of siblings she choose 200 students.
So, here the sample should be 200 randomly selected students.
Therefore the other options should be incorrect.
Thus we can conclude that the sample is 200 randomly selected students.
Learn more about the sample here: brainly.com/question/13287171
Answer:
what are the statements
Step-by-step explanation:
