200.123.4.6 is a classful internet protocol (ip) address located in class C.
An IP address (internet protocol address) is a numeric representation. This numerical representation uniquely identifies a particular interface on the network.
Address in IPv4 that has a length of 32 bits. This allows a maximum of 4,294,967,296 (232) unique addresses. Addresses in IPv6 are 128-bits long, which allows for 3.4 x 1038 (2128) unique addresses.
The total usable address pools of both versions are subtracted by the various reserved addresses and other considerations.
IP addresses can also be defined as binary numbers but are usually expressed in decimal form (IPv4) or hexadecimal form (IPv6) to make it easier for humans to read and use them.
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Answer:
The correct option is b. He is a good communicator , he is a motivator, he can keep a secret and lastly he can quickly learn about operating systems.
Explanation:
Based on the information given what best explains why Keith was in charge of the project and was qualified for such a position was that he has a great Communication skills because he communicate and relate with customers in a great ways and he is a good listener.
Secondly he posses confidentiality skills which is a very important skills for a business or an organization.
Lastly he his a fast learner who has the ability to quickly learn and know about everything that has to do with an operating system which is the reason why he was qualified to be in such position and was put in charge of the project based on all the important skills mentioned above that he possess.
Answer:
April 30, 1993
Explanation:
On April 30, 1993, four years after publishing a proposal for “an idea of linked information systems,” computer scientist Tim Berners-Lee released the source code for the world’s first web browser and editor.
The process where the programmer steps through each of the program's statements one by one is called 
.
Answer:
Probability Distribution={(A, 4/7), (B, 2/7), (C, 1/7)}
H(X)=5.4224 bits per symb
H(X|Y="not C")=0.54902 bits per symb
Explanation:
P(B)=2P(C)
P(A)=2P(B)
But
P(A)+P(B)+P(C)=1
4P(C)+2P(C)+P(C)=1
P(C)=1/7
Then
P(A)=4/7
P(B)=2/7
Probability Distribution={(A, 4/7), (B, 2/7), (C, 1/7)}
iii
If X={A,B,C}
and P(Xi)={4/7,2/7,1/7}
where Id =logarithm to base 2
Entropy, H(X)=-{P(A) Id P(A) +P(B) Id P(B) + P(C) Id P(C)}
=-{(1/7)Id1/7 +(2/7)Id(2/7) +(4/7)Id(4/7)}
=5.4224 bits per symb
if P(C) =0
P(A)=2P(B)
P(B)=1/3
P(A)=2/3
H(X|Y="not C")= -(1/3)Id(I/3) -(2/3)Id(2/3)
=0.54902 bits per symb
