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3 years ago

The graph shows motion of a train. Enter a value to complete the statement

Mathematics

2 answers:

olya-2409 [2.1K]3 years ago

8 0

Answer:

25, i had the same question

schepotkina [342]3 years ago

4 0

Answer:25

Cause it is I tried it

Step-by-step explanation:

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Find the Inverse of 3x^3-1=y

Anika [276]

$y = 3x^{3} - 1$
$x = 3y^{3} - 1$
$3y^{3} = x + 1$
$y^{3} = \frac{x + 1}{3}$

$y = \sqrt[3]{\frac{x + 1}{3}}$

5 0

3 years ago

The quotient of a number and - 2/3 is -9/10.

Ad libitum [116K]

It would be: -2/3 * -9/10 = 18/30 = 3/5

So, option B is your answer.

Hope this helps!

6 0

3 years ago

Read 2 more answers

At 8:00, the temperature was -6°. Three hours later, the temperature dropped 13°. What is the temperature at 11:00?

AysviL [449]

Answer:

-19 degrees

Step-by-step explanation:

13+6=19

you would need to add the negative since it said dropped in temperature and the temperature was already negative.

3 0

2 years ago

Please help me, i will give you brainliest

True [87]

Answer:

Step-by-step explanation:

(segment piece) x (segment piece) = (segment piece) x (segment piece)

JN* NK = LN * NM

3x = 2*6

3x = 12

Divide by 3

3x/3 =12/3

x =4

6 0

3 years ago

How does the graph of f(x)=3lx+2l+4 relate to its parent function?

Sergeeva-Olga [200]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
\end{array}$

now, with that template above in mind, let's see this one

$\bf parent\implies f(x)=|x|
\\\\\\
\begin{array}{lllcclll}
f(x)=&3|&1x&+2|&+4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}$

A=3, B=1, shrunk by AB or 3 units, about 1/3
C=2, horizontal shift by C/B or 2/1 or just 2, to the left
D=4, vertical shift upwards of 4 units

check the picture below

7 0

3 years ago