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3 years ago

If the probability of rain is 31%. What is the probability of it not raining?

Mathematics

2 answers:

-Dominant- [34]3 years ago

5 0

Answer:

69%

Step-by-step explanation:

Since we only have two options, rain or not rain, they have to add to 100%

100 -31 = 69

So not raining is 69%

jeka943 years ago

5 0

Answer:

69%

Step-by-step explanation:

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Hello :
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3 years ago

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s344n2d4d5 [400]

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2 years ago

The polynomial p(x)=x^3-6x^2+32p(x)=x 3 −6x 2 +32p, left parenthesis, x, right parenthesis, equals, x, cubed, minus, 6, x, squar

Ray Of Light [21]

Answer:

(x-4)(x-4)(x+2)

Step-by-step explanation:

Given p(x) = x^3-6x^2+32 when it is divided by x - 4, the quotient gives

x^2-2x-8

Q(x) = P(x)/d(x)

x^3-6x^2+32/x- 4 = x^2-2x-8

Factorizing the quotient

x^2-2x-8

x^2-4x+2x-8

x(x-4)+2(x-4)

(x-4)(x+2)

Hence the polynomial as a product if linear terms is (x-4)(x-4)(x+2)

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3 years ago

What do I do for this problem

slamgirl [31]

To divide fractions, you need to multiply by the reciprocal. The reciprocal of 3/4 is 4/3, which is why the work is incorrect.

See attached:

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3 years ago

Which of the following is a solution to 2cos2x − cos x − 1 = 0?

Pavel [41]

Answer:

Option A is correct.

Solution for the given equation is, $x = 0^{\circ}$

Step-by-step explanation:

Given that : $2\cos^2x -\cos x -1 =0$

Let $\cos x =y$

then our equation become;

$2y^2-y-1= 0$ .....[1]

A quadratic equation is of the form:

$ax^2+bx+c =0$ .....[2] where a, b and c are coefficient and the solution is given by;

$x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Comparing equation [1] and [2] we get;

a = 2 b = -1 and c =-1

then;

$y = \frac{-(-1)\pm \sqrt{(-1)^2-4(2)(-1)}}{2(2)}$

Simplify:

$y = \frac{ 1 \pm \sqrt{1+8}}{4}$

$y = \frac{ 1 \pm \sqrt{9}}{4}$

$y = \frac{ 1 \pm 3}{4}$

$y = \frac{1+3}{4}$ and $y = \frac{1 -3}{4}$

Simplify:

y = 1 and $y = -\frac{1}{2}$

Substitute y = cos x we have;

$\cos x = 1$

⇒ $x = 0^{\circ}$

and

$\cos x = -\frac{1}{2}$

⇒ $x = 120^{\circ} \text{and} x = 240^{\circ}$

The solution set: $\{0^{\circ}, 120^{\circ} , 240^{\circ}\}$

Therefore, the solution for the given equation $2\cos^2x -\cos x -1 =0$ is, $0^{\circ}$

8 0

3 years ago

Read 2 more answers