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Plz help !!!!!!!! A rectangular park is 400 m long and 200 m wide. If you walked around the park twice, how far would you walk?

aliina [53]

Answer:

160,000

Step-by-step explanation:

400 * 200 is 80,000 just walking around once, so then multiply it by two.

80,000 * 2 is 160,000

4 0

3 years ago

Write an equation of a line that passes through (1,1)and (6,6)

Ghella [55]

Answer:

y=x

Step-by-step explanation:

When y=x, then the line goes up 1 and right 1.

7 0

2 years ago

Find the surface area of a square pyramid with a base length of 24 cm and a height of 16 cm. Explain how you solved the problem.

icang [17]

Answer:

the answer b

Step-by-step explanation:

[surface area]=[area of 4 triangles sides]+[area of square base]

[area of square base]=24*24--------> 576 cm²

[area of one triangles side]

l=slant height

l²=16²+12²-------> l²=400-----------> l=20 cm

[area of one triangles side]=24*20/2--------> 240 cm²

[area of 4 triangles sides]=4*240----------> 960 cm²

[surface area]=[960]+[576]--------> 1536 cm²

6 0

2 years ago

Six sophomores and 14 freshmen are competing for two alternate positions on the debate team. Which expression represents the pro

Elanso [62]

Answer:

<em>Choose the first alternative</em>

$\displaystyle P=\frac{_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C}}{_{2}^{20}\textrm{C}}$

Step-by-step explanation:

<u>Probabilities</u>

The requested probability can be computed as the ratio between the number of ways to choose two sophomores in alternate positions $(N_s)$ and the total number of possible choices $(N_t)$ , i.e.

$\displaystyle P=\frac{N_s}{N_t}$

There are 6 sophomores and 14 freshmen to choose from each separate set. There are 20 students in total

We'll assume the positions of the selections are NOT significative, i.e. student A/student B is the same as student B/student A.

To choose 2 sophomores out of the 6 available, the first position has 6 elements to choose from, the second has now only 5

$_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C} \text{ ways to do it}$

The total number of possible choices is

$_{2}^{20}\textrm{C} \text{ ways to do it}$

The probability is then

$\boxed{\displaystyle P=\frac{_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C}}{_{2}^{20}\textrm{C}}}$

Choose the first alternative

7 0

2 years ago

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Write the equation that represents the relationship between n the number of triangles and p the perimeter of the figures formed.

Klio2033 [76]

1 triangle: 2*6 + 1*5

2 triangles: 2*6 + 2*5

3 triangles: 2*6 + 3*5

So for n triangles: p = 2*6 + n*5 = 12 + 5n

4 0

3 years ago

Read 2 more answers