We are given f(x) =3x and g(x) =2x
Now we have to find (g*f)(x).
so (g*f)(x) means we multiply f(x) and g(x).
So multiplying 3x and 2x,
3x * 2x = 6x²
So (g*f)(x) =6x²
Let
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The exponent is indeed
- not a typo!
Take the antiderivative of
, denoted by
. This recovers a factor of
in the denominator, which lets us condense it to a single factorial.

Recall the series expansion of sine,
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Then with a little algebraic manipulation, we get
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Differentiate to recover
.
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Finally,
, so our sum is

Answer:
$29.26
Step-by-step explanation:
27/100=0.27
0.27*8=2.16
27.00+2.16=29.16
hope this helps!
Answer:
idk
Step-by-step explanation: