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1 year ago

The chart below shows conversion between kilometers and miles.

Mathematics

1 answer:

lara31 [8.8K]1 year ago

3 0

Don’t touch my truck!!!…….

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Which of the following groups are subsrts of rational numbers

Anna [14]

There has to be more to this question then i can help you

5 0

3 years ago

Plzzz guys help I'm so confused

GalinKa [24]

Answer:

x = number of years

(the ^ before the x symbolizes "to the power of," but I can't do that on my keyboard)

Step-by-step explanation:

formula i used:

A = <em>amount that you start with</em>

t = amount of years / time

%increase: you must convert your percent (4.8%) to a decimal (0.048)

A ( 1 + %increase ) ^t

4 0

2 years ago

Read 2 more answers

Select all the pairs of equivalent expressions.

iren2701 [21]

Answer:

$\huge\boxed{(3^4)^4=3^8\cdot3^8}\\\boxed{4^3\cdot5^3=20^3}\\\boxed{(4^3)^3=4^3\cdot4^3\cdo4^3}$

Step-by-step explanation:

$a^n\cdot a^n=a^{n+m}\\\\(a^n)^m=a^{n\cdot m}\\\\(a\cdot b)^n=a^n\cdot b^n\\=====================$

$(4^3)^3=4^{3\cdot3}=4^9\\4^3\cdot4^3=4^{3+3}=4^6\\\\4^9\neq4^6\to(4^3)^3\neq4^3\cdot4^3\\==================$

$(3^4)^4=3^{4\cdot4}=3^{16}\\3^8\cdot3^8=3^{8+8}=3^{16}\\\\(3^4)^4=3^8\cdot3^8\\================$

$6^4\cdot3^4=(6\cdot3)^4=18^4\\\\18^4\neq18^8\to6^4\cdot3^4\neq18^8\\=================$

$4^3\cdot5^3=(4\cdot5)^3=20^3\\\\4^3\cdot5^3=20^3\\=================$

$(4^3)^3=4^{3\cdot3}=4^9\\4^3\cdot4^3\cdot4^3=4^{3+3+3}=4^9\\\\(4^3)^3=4^3\cdot4^3\cdot4^3$

3 0

3 years ago

Find the measure of angle x. Round your answer to the nearest hundredth. (Numeral answers only)

gregori [183]

Sin (Angle) = Opposite / Hypotenuse

Sin (X) = 8/17

X = Arcsin(8/17)

X = 28.07 degrees.

6 0

3 years ago

Read 2 more answers

Prove that if sin (2 + y) = 3 sin (x - y), then tan x = 2 tany.

nignag [31]

Answer:

The proof is given below.

Step-by-step explanation:

Given: ( the correct question and ans is as follow )

sin (x + y) = 3sin ( x - y)

To Prove

tan x = 2 tan y

Proof:

$\sin (x+y) = 3\sin (x-y)$

Using the identities

$\sin (A+B) = \sin A.\cos B + \cos A.\sin B\\and\\\sin (A-B) = \sin A.\cos B - \cos A.\sin B\\$

we get

$\sin x.\cos y + \cos x.\sin y = 3(\sin x.\cos y - \cos x.\sin y)\\\sin x.\cos y + \cos x.\sin y = 3\sin x.\cos y - 3\cos x.\sin y$

Now we will take sin x . cos y to the left hand side and cos x . sin y to the right hand side,we get

$3\sin x.\cos y - \sin x.\cos y = 3\cos x.\sin y +\cos x.\sin y\\2\sin x.\cos y =4\cos x.\sin y\\\sin x.\cos y =2\cos x.\sin y \ \textrm{4 divide by 2}\\ \frac{\sin x}{\cos x} =2\times \frac{\sin y}{\cos y} \\\textrm{we know identity }\\\frac{\sin x}{\cos x} = \tan x\\\frac{\sin y}{\cos y} = \tan y\\\therefore \tan x = 2\tan y\ ...............{PROVED}$

7 0

3 years ago