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Olenka [21]
3 years ago
9

HElp TesT No G0oD SORRY FREAKING OUT

Geography
2 answers:
Brums [2.3K]3 years ago
8 0
Breathe and calm down, you got this
(^∇^)
Mariana [72]3 years ago
8 0
pretty sure C is the answer
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Which is an accurate definition of dialect<br>​
Goshia [24]

Answer:

A regional or social variety of a language distinguished by pronunciation, grammar, or vocabulary, especially a variety of speech differing from the standard literary language or speech pattern of the culture in which it exists.

or

A variety of language that with other varieties constitutes a single language of which no single variety is standard.

Hope this helps :)

4 0
2 years ago
Read 2 more answers
Please help me answer this will brainleist and 15 points
LenKa [72]
I believe the answer is "D"
4 0
3 years ago
(06. 02 MC)
Serhud [2]

Answer:

it diameter of wooden fence post. He's one ft and height of who then fence post. He called to six ft. The surface area of one would in fence post huge by B. S. Plus to buy our square. This equal to six 3.14 into one into six Plus two into 3.14 into one by two square. So this is equal to 18.84 plus 1.57 feet is square. This is equal to 20 hold one feed is square. So the surface area for 12 Friends First is 20 .41 into 12, Which is equal to 244 .92 ft Square. Does the amount of paint required to paint all the surface of the face Post? Age 2 4 4.92 ft Square. Thank youyou

Explanation:

6 0
3 years ago
What is the value of X6? <br><br> Show the solution.
wariber [46]

Answer : The value of x_6 is \sqrt{7}.

Explanation :

As we are given 6 right angled triangle in the given figure.

First we have to calculate the value of x_1.

Using Pythagoras theorem in triangle 1 :

(Hypotenuse)^2=(Perpendicular)^2+(Base)^2

(x_1)^2=(1)^2+(1)^2

x_1=\sqrt{(1)^2+(1)^2}

x_1=\sqrt{2}

Now we have to calculate the value of x_2.

Using Pythagoras theorem in triangle 2 :

(Hypotenuse)^2=(Perpendicular)^2+(Base)^2

(x_2)^2=(1)^2+(X_1)^2

(x_2)^2=(1)^2+(\sqrt{2})^2

x_2=\sqrt{(1)^2+(\sqrt{2})^2}

x_2=\sqrt{3}

Now we have to calculate the value of x_3.

Using Pythagoras theorem in triangle 3 :

(Hypotenuse)^2=(Perpendicular)^2+(Base)^2

(x_3)^2=(1)^2+(X_2)^2

(x_3)^2=(1)^2+(\sqrt{3})^2

x_3=\sqrt{(1)^2+(\sqrt{3})^2}

x_3=\sqrt{4}

Now we have to calculate the value of x_4.

Using Pythagoras theorem in triangle 4 :

(Hypotenuse)^2=(Perpendicular)^2+(Base)^2

(x_4)^2=(1)^2+(X_3)^2

(x_4)^2=(1)^2+(\sqrt{4})^2

x_4=\sqrt{(1)^2+(\sqrt{4})^2}

x_4=\sqrt{5}

Now we have to calculate the value of x_5.

Using Pythagoras theorem in triangle 5 :

(Hypotenuse)^2=(Perpendicular)^2+(Base)^2

(x_5)^2=(1)^2+(X_4)^2

(x_5)^2=(1)^2+(\sqrt{5})^2

x_5=\sqrt{(1)^2+(\sqrt{5})^2}

x_5=\sqrt{6}

Now we have to calculate the value of x_6.

Using Pythagoras theorem in triangle 6 :

(Hypotenuse)^2=(Perpendicular)^2+(Base)^2

(x_6)^2=(1)^2+(X_5)^2

(x_6)^2=(1)^2+(\sqrt{6})^2

x_6=\sqrt{(1)^2+(\sqrt{6})^2}

x_6=\sqrt{7}

Therefore, the value of x_6 is \sqrt{7}.

5 0
3 years ago
As the Earth is covered by the Moon's shadow, it will get
goldfiish [28.3K]
I believe the correct answer would be (b)
5 0
4 years ago
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