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Andru [333]
3 years ago
15

Write each decimal in words. 4. 0.8 5. 400.29 6. 0.0306

Mathematics
1 answer:
Anarel [89]3 years ago
7 0

Answer: four, zero, eighty five, four hundred and two hundred ninety six hundredth, zero and three hudred and six thousandsths  

Step-by-step explanation:

You might be interested in
What is the constant rate of change of the graph below?
timofeeve [1]

Answer:

the constant rate of change is 20

5 0
3 years ago
Find the exact value of csc ø, if cos ø= 1/9; 180° less ø less than 270°
Iteru [2.4K]

Answer:

The answer to your question is: the first option  - 9/ \sqrt{80}

Step-by-step explanation:

Process

          cosФ = adjacent side / hypotenuse

          -1/9 = adjacent side / hypotenuse

          adjacent side = -1    hypotenuse = 9

          c² = a² + b²

          b² = c² - a²

           b² = 81 - 1

           b = \sqrt{80} \\    b = opposite side

But b is negative because we are in the third quadrant.

          b = -\sqrt{80}

Finally   csc Ф = hypotenuse / opposite side

             csc Ф = - 9 / \sqrt{80}

4 0
3 years ago
A bottle contains 1.7 L of water. A second bottle contains 450 mL of water. What is the total number of mL of water in both bott
amm1812

Answer:

2150 mL

Step-by-step explanation:

1L=1000mL - convert

1.7mL=1700mL - convert problem numbers

1700+450mL - addition

2150mL- answer

5 0
3 years ago
PLEASE HELP GUYS i am struggling so much, two questions
ankoles [38]

Answer: the equation of the standard parabola

1) (y-6)^2 = 4 (x-1)

The equation of the standard parabola

2) (x+5)^2 = 16(y-2)

Step-by-step explanation:

<u>Explanation </u>

<u>Parabola:-</u>

The set of points in a plane whose distance from a fixed point and a constant ratio to their corresponding perpendicular distance from a fixed straight line is a conic.

Let S be a fixed point and l be a fixed straight line from any point P,the perpendicular PM is drawn to the line 'l'

  • The locus of P such that \frac{SP}{PM} = constant
  • The fixed point  'S' is called the Focus.
  • The fixed line'l 'is called the directrix of the conic
  • The constant ratio is known as the eccentricity, denoted by 'e'
  • If e=1 , the conic is called a parabola

1) <u> Step 1</u> :-

Given the focus   S = (2,6) and directrix is x=0

we know that \frac{SP}{PM}=1

now cross multiplication , we get

SP = PM

squaring on both sides,we get

SP^{2} = PM^2

step 2:-

now using distance formula is

  • \sqrt(((x_{2}-x_{1})^2+(y_{2} -y_{1} )^2)

Given S =(2,6) and P(x,y) be any point on parabola

SP^2 = (x-2)^2+(y-6)^2........(1)

Now using perpendicular distance formula

let P(x , y ) be any point on the parabola

  • \frac{ax_{1}+by_{1}+c   }{\sqrt{a^2+b^2} }

Given the directrix is x =0 and P(x,y) be any point on parabola

PM^2 = \frac{x^2}{\sqrt{1}^2 }......(2)

equating equation(1) and equation (2), on simplification

we get (x-2)^2+(y-6)^2 = x^2.....(3)

  • apply (a-b)^2 = a^2+  b^2+2 ab

now the equation (3) is

(y-6)^2 = 4 x-4

now the standard form of parabola is

(y-k)^2 = 4 a(x-h)

<u>Final answer</u>:-

(y-6)^2 = 4 (x-1)

2) <u> Explanation:-</u>

<u>step 1:</u>

Given vertex of a parabola is A(-5,2) and its focus is S(-5,6)

here the given points of 'x'co- ordinates are equal

  • Therefore the axis AS is parallel to y- axis

now the standard equation of parabola

(x-h)^2 = 4 a (y-k)

now you have to find' a' value

Given vertex of a parabola is A(-5,2) and its focus is S(-5,6)

The distance of AS = \sqrt{(-5-(-5)^2+(2-6)^2}

 on simplification we get a =4

<u>Final answe</u>r :-

the vertex (h,k) = (-5,2) and a=4

(x-h)^2 = 4 a (y-k)

The standard parabola is (x+5)^2 = 16 (y-2)

5 0
3 years ago
Which graph shows a set of ordered pairs that represent a function? Image for option 1 Image for option 2 Image for option 3 Ima
wariber [46]

where's the <u>image</u>

pls provide the full information.

5 0
3 years ago
Read 2 more answers
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