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3 years ago

Solve for the indicated variable. 5y + 4x = 6 for x solve for x x=

Mathematics

1 answer:

katrin2010 [14]3 years ago

6 0

Answer:

x = 3/2 - 5y/4

Step-by-step explanation:

5y + 4x = 6

-5y -5y

4x = 6-5y

/4 /4 /4

x = 6/4 - 5y/4

x = 3/2 - 5y/4

Move all terms that don't contain x to the right side and solve.

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Help pleaseeee ASAP just tell me the answer

iragen [17]

HEY MATE YOUR ANSWER IS HERE

★ GIVEN EQUATION ★

X + Y = 4

★ SOLUTION ★

LET VALUE OF X = 0 , 1 , 2 , 3 AND 4

WHEN X = 0

0 + Y = 4

Y = 4

WHEN X = 1

1 + Y = 4

Y = 3

WHEN X = 2

2 + Y = 4

Y = 2

WHEN X = 3

3 + Y = 4

Y = 1

WHEN X = 4

4 + Y = 4

Y = 0

NOW OUR 5 COORDINATES OF LINE X + Y = 4 ARE

A ( 0 , 4)

B ( 1 , 3 )

C ( 2 , 2)

D ( 3 , 1 )

E ( 4 , 0 )

THANKS FOR YOUR QUESTION HOPE THIS HELPS

can i have a brill

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6 0

3 years ago

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vredina [299]

70 kilometers because you have to multiply 3.5 by 20.

3 0

3 years ago

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Does anyone know what the y-int is please help

tester [92]

I’m pretty sure it’s 1

5 0

3 years ago

Read 2 more answers

Asking for help in the following question #1 and #2 are based of algebra 2.<br><br> ≅<br> ⇒⇒⇒⇒⇒⇒

Orlov [11]

Answer:

Step-by-step explanation:

For the first one, revenue - cost = profit. We have equations for revenue and profit, so filling in:

$-.3x^2+150x-cost=-.5x^2+250x-300$

Let's add cost to both sides to make it positive and bring everything on the right over to the left and combine like terms:

$.2x^2-100x+300=cost$

For the second one:

P(x)*T(x) = $(x^2-3x-7)(3x)$

Distribute the 3x into everything inside the parenthesis to get

$3x^3-9x^2-21x$

For the second part of that problem, C(x)*P(x) = $(x-4)(x^2-3x-7)$

Distribute the x into everything first to get:

$x^3-3x^2-7x$

The distribute the -4 into everything to get:

$-4x^2+12x+28$

Combine the like terms and put everything together to get

$x^3-7x^2+5x+28$

7 0

3 years ago

ABCD is an 8 by 6 rectangle. AC is a diagonal with length 10. Point E is on AC such that BE is perpendicular to AC . What is the

anyanavicka [17]

Answer:

The length of BE is 5 units.

Step-by-step explanation:

ABCD is rectangle

AC is a diagonal and BD is a diagonal too.

Diagonals of rectangle are equal and bisect each other perpendicularly.

So, AE = BE

AE = 1/2 × AC

= 1/2 × 10

= 5

BE = 5

Hence the length of BE is 5 units.

4 0

2 years ago